Update on filtering table

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Kyle Koutonen
Kyle Koutonen 2021년 3월 1일
편집: Cris LaPierre 2021년 3월 1일
I posted a question on here the other day about filtering and it hasn't been answered yet, i made some changes to it but still have issue so I'm hoping if there are two posts one will be answered. So i made the loop to store which rows have values over the cut off value, the only problem is when row is under the cut off value a zero is put into the rows delt vector which screws up the deleteing of rows since the Table cannot have a zero input.
Filter=app.CutOffValueEditField.Value;
n=size(app.t,1);
if(app.LowPassButton.Value)
for i=1:n
if app.UITable3.Data(i,app.ColumnNumberbeingevalulatedEditField.Value)>=Filter
rowsdelt(i)=i
end
end
app.UITable3.Data(rowsdelt,:)=[];

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Cris LaPierre
Cris LaPierre 2021년 3월 1일
편집: Cris LaPierre 2021년 3월 1일
Use logical indexing instead. You can do that without the for loop. (untested)
if ...
rowsdelt = app.UITable3.Data(:,app.ColumnNumberbeingevalulatedEditField.Value)>=Filter;
app.UITable3.Data(rowsdelt,:)=[];
end
Note that you'll want the delete command inside the if statement or you'll get an error about undefined variable rowsdelt anytime app.lowpassbutton.value is false.

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