Producing a NaN only where there is a NaN, zero otherwise
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This interesting question came up for me today. I was looking for a simple expression that can be used in a function handle, one that produces a NaN only for elements that are already NaN, but I want it to return 0 for any other element, including +/- inf.
X = [-inf, -1, -eps, 0, realmin, 2, 1+i, pi, flintmax, realmax, inf, NaN];
That should qualify as a good list of the possible numbers in MATLAB that might be of interest.
I want my function to generate a result as the vector: [0 0 0 0 0 0 0 0 0 0 0 NaN].
For example, this fails:
broken1 = @(X) 0*X;
broken1(X)
Though it is close. It suffers because 0*inf generates a NaN. An as pretty one is:
broken2 = @(X) X - X;
broken2(X)
It fails for a similar reason, because inf-inf produces NaN.
A valid solution should work for arrays of any shape or size of course. Yes, it is trivial to write if I do it in an m-file. Thus...
nanZ(X)
function res = nanZ(X)
% returns a NaN ONLY for elements of X that are NaN. All other elements will generate zero.
res = zeros(size(X));
res(isnan(X)) = NaN;
end
As I said, trivial if I use an m-flle. More difficult if I wish to use a function handle. It may be a blind spot on my part. But as a puzzle, can you write a simple, robust one line expression to produce my desired result, expressed as a function handle? Vectorized, of course.
And yes, I'll admit this question has essentially zero value, since a valid solution exists in an m-file form. Have fun! (I'll post a spoiler as an answer if people cannot find a better solution than the one I found. My final solution required only 9 characters, but it was definitely non-obvious.)
댓글 수: 2
답변 (6개)
Stephen23
2021년 2월 22일
X = [-inf, -1, -eps, 0, realmin, 2, 1+i, pi, flintmax, realmax, inf, NaN];
Y = 0./(X==X)
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the cyclist
2021년 2월 22일
편집: the cyclist
2021년 2월 22일
0./eq(X,X)
is a nice variant of this, but one additional character
Gustavo Lunardon
2021년 3월 24일
Added as an answer rather than a comment now
X = [-inf, -1, -eps, 0, realmin, 2, 1+i, pi, flintmax, realmax, inf, NaN];
broken1 = @(X) 0./X.^0;
broken1(X)
Also works, 7 characters
X = [-inf, -1, -eps, 0, realmin, 2, 1+i, pi, flintmax, realmax, inf, NaN];
broken1 = @(X) 0*X.^0;
broken1(X)
Works as well with 6 characters
Advantage is that you can put any number different than zero in the other elements by changing the multiplier
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the cyclist
2021년 3월 24일
Very nice!
It's a darn shame that
not(NaN)
does not yield NaN, because "NaN cannot be converted to logical". If it did, then
~X.^0
would be a sublime 5-character solution.
the cyclist
2021년 2월 22일
편집: the cyclist
2021년 2월 22일
First attempt:
X = [-inf, -1, -eps, 0, realmin, 2, 1+i, pi, flintmax, realmax, inf, NaN];
broken = @(x) 1./((isnan(x)-1)/0); % 19 characters
broken(X)
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the cyclist
2021년 2월 22일
Second attempt ...
X = [-inf, -1, -eps, 0, realmin, 2, 1+i, pi, flintmax, realmax, inf, NaN];
broken = @(x) 0./(isnan(x)-1); % 15 characters
broken(X)
댓글 수: 2
the cyclist
2021년 2월 23일
I overlooked the obvious improvement to this one:
broken = @(x) 0./~isnan(x); % 12 characters
I like the fact that this one avoids the annoying denominator parentheses
Jan
2021년 3월 24일
X = [-inf, -1, -eps, 0, realmin, 2, 1+i, pi, flintmax, realmax, inf, NaN];
V = [0, NaN];
F = @(X) V(isnan(X) + 1);
F(X)
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John D'Errico
2021년 2월 22일
편집: John D'Errico
2021년 2월 22일
댓글 수: 2
Gustavo Lunardon
2021년 3월 24일
편집: Gustavo Lunardon
2021년 3월 24일
X = [-inf, -1, -eps, 0, realmin, 2, 1+i, pi, flintmax, realmax, inf, NaN];
broken1 = @(X) 0./X.^0;
broken1(X)
Also works, 7 characters
X = [-inf, -1, -eps, 0, realmin, 2, 1+i, pi, flintmax, realmax, inf, NaN];
broken1 = @(X) 0*X.^0;
broken1(X)
Works as well with 6 characters
Advantage is that you can put any number different than zero in the other elements by changing the multiplier
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