mkdir with variable name

Hi, i want to make directory. This directory is in a directory which name depends on a variable. How can i do this? This is part of my code.

    for l=1:10
       ...
       mkdir('c:\...\demence\' int2str(l) '\','coef')
       ...
    end

It is not working. Thanks for help.

Answer 1

[Sean de Wolski]

See the first example here:

http://www.mathworks.com/matlabcentral/answers/57446

You're close:

mkdir(['c:' 'c:\...\demence\' int2str(l) '\']);

or

mkdir(sprintf('c:\%i',l))

[Jakub]

I asked worng question. I want to make directory 'coef' in a directory that depends on a variable 'l'...

[Sean de Wolski]

How is that any different?

   mkdir a\b\c

You can make sub directories with mkdir

[Jakub]

It shouldnt be but its not working...

 mkdir('c:\test\' int2str(l) '\','koef')
 mkdir('c:\test\' int2str(l) '\','koef')
                 |
Error: Unexpected MATLAB expression._**

[Sean de Wolski]

You need to put the string inside of square brackets to concatenate it first, just like I did.

Answer 2

[Anmol Pardeshi]

for a=1:1000
 subfolder_name=char(%pick information from a variable whos folder name is expected and store here);
 cd F:\OutputFolder      %route to the parent folder of output
 mkdir(['F:\OutputFolder\',subfolder_name])
 ...
end

[Walter Roberson]

projectdir = 'F:\OutputFolder';

for a = 1 : 1000
   subfolder_name=char(%pick information from a variable whos folder name is expected and store here);
   mkdir( fullfile(projectdir, subfolder_name) );
end