What is the standard code for solving any cubic equation

I have been asked to submit the standard code for solving any cubic equation but I do not know?need help ASAP .

답변 (3개)

Anas
Anas 2025년 1월 28일
편집: Matt J 2025년 1월 28일
% Simple Cubic Equation Solver
clc;
clear;
% Input coefficients for the cubic equation ax^3 + bx^2 + cx + d = 0
a = input('Enter coefficient a (for x^3): ');
b = input('Enter coefficient b (for x^2): ');
c = input('Enter coefficient c (for x): ');
d = input('Enter constant d: ');
% Check if it's a valid cubic equation
if a == 0
disp('This is not a cubic equation.');
else
% Define polynomial coefficients and solve
coefficients = [a b c d];
roots_cubic = roots(coefficients);
% Display the roots
disp('The roots of the cubic equation are:');
disp(roots_cubic);
end
syms a b c d x
R = solve(a*x^3 + b*x^2 + c*x + d == 0, x, 'maxdegree', 3);
matlabFunction(R, 'file', 'CubicSolver.m', 'vars', {a b c d} )
ans = function_handle with value:
@CubicSolver
dbtype CubicSolver.m
1 function R = CubicSolver(a,b,c,d) 2 %CubicSolver 3 % R = CubicSolver(A,B,C,D) 4 5 % This function was generated by the Symbolic Math Toolbox version 24.2. 6 % 28-Jan-2025 17:53:38 7 8 t2 = b.^2; 9 t3 = b.^3; 10 t4 = 1.0./a; 11 t7 = sqrt(3.0); 12 t5 = t4.^2; 13 t6 = t4.^3; 14 t8 = (b.*t4)./3.0; 15 t9 = (c.*t4)./3.0; 16 t10 = (d.*t4)./2.0; 17 t11 = -t8; 18 t12 = -t10; 19 t13 = (b.*c.*t5)./6.0; 20 t15 = (t2.*t5)./9.0; 21 t16 = (t3.*t6)./2.7e+1; 22 t14 = -t13; 23 t17 = -t15; 24 t18 = -t16; 25 t19 = t9+t17; 26 t21 = t10+t14+t16; 27 t20 = t19.^3; 28 t22 = t21.^2; 29 t23 = t20+t22; 30 t24 = sqrt(t23); 31 t25 = t12+t13+t18+t24; 32 t26 = t25.^(1.0./3.0); 33 t27 = 1.0./t26; 34 t28 = t26./2.0; 35 t29 = -t28; 36 t30 = t19.*t27; 37 t31 = t30./2.0; 38 t32 = t26+t30; 39 t33 = t7.*t32.*5.0e-1i; 40 R = [t11+t26-t30;t11+t29+t31-t33;t11+t29+t31+t33]; 41 end
Now CubicSolver.m exists in your current directory, and can be called with four parameters that are compatible in size (but best if they are scalars or row vectors.)

카테고리

도움말 센터File Exchange에서 Polynomials에 대해 자세히 알아보기

질문:

2013년 5월 7일

답변:

2025년 1월 28일

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