function performance, same functions has very different speed

조회 수: 1 (최근 30일)
Alexander Malafeev
Alexander Malafeev 2013년 5월 2일
Dear forum, I have two functions
function [Md] = MDx( M, dx )
w = size(M,2);
for i=2:w-1
Md(:,i) = ( M(:,i+1) - M(:, i-1) )/(2*dx);
end
Md(:,1) = ( M(:,2) - M(:, 1) )/dx;
Md(:,w) = ( M(:,w) - M(:, w-1) )/dx;
return
and
function [Md] = MDy( M, dy )
h = size(M,1);
for i=2:h-1
Md(i,:) = ( M(i+1,:) - M(i-1, :) )/(2*dy);
end
Md(1,:) = ( M(2,:) - M(1, :) )/dy;
Md(h,:) = ( M(h,:) - M(h-1,:) )/dy;
return
this functions are computing gradient in X and Y directions, they are quite same but on square matrix MDx is 40 times faster than MDy, what is the reason for that?

답변 (1개)

John Doe
John Doe 2013년 5월 2일
편집: John Doe 2013년 5월 2일
I believe this is due to the way matrices are stored in Matlab.
A matrix is stored column-wise, as below:
A = [1 2 3;4 5 6;7 8 9];
A(1,1) = A(1) = 1;
A(2,1) = A(2) = 4;
...
A(1,3) = A(7) = 3;
A(:,1) = A(1:3);
A(1,:) = A([1 4 7]);
This makes it faster to do calculations on entire columns, rather than rows, thus MDx is fastest.

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