Im trying to define a square wave that starts only after 0.01 milliseconds. The code is below. The amplitude and frequency are both correct from the code below but it starts immediately from time 0 rather than from time 0.01, as if the if statement below is always true. what is going wrong?
t= linspace(0,0.03,1000);
i_block = 0;
for k = 1:1000
t(k)
if t(k) >= 0.01
i_block = mod(t/period, 1) > 0.5;
i_block = -2*I*i_block + I;
end;
end;

댓글 수: 2

Azzi Abdelmalek
Azzi Abdelmalek 2013년 4월 30일
What is I?
Joe Koning
Joe Koning 2013년 4월 30일
ah sorry, I is the required amplitude, in this case I = 20000; period = 1/2000

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 채택된 답변

Azzi Abdelmalek
Azzi Abdelmalek 2013년 4월 30일
편집: Azzi Abdelmalek 2013년 4월 30일

0 개 추천

t= linspace(0,0.03,1000);
period=0.03/10
I=10
i_block = 0;
for k = 1:1000
t(k)
if t(k) >= 0.01
i_block(k) = mod(t(k)/period, 1) > 0.5;
i_block(k) = -2*I*i_block(k) + I;
end;
end;
plot(t, i_block,'r')

댓글 수: 2

or
t= linspace(0,0.03,1000);
period=0.03/10
I=10
idx=find(t>=0.01)
i_block(1:idx(1)-1)=0
i_block(idx) = mod(t(idx)/period, 1) > 0.5
i_block(idx) = -2*I*i_block(idx) + I
plot(t, i_block,'r')
Joe Koning
Joe Koning 2013년 4월 30일
ahhh of course, thankyou

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추가 답변 (1개)

Wharengaro Ruha
Wharengaro Ruha 2019년 10월 2일

0 개 추천

I need to make a square wave
at 1v for 2000s
then -1v for 2000s
then 1v for 4000s
then -1v for 6000s
then 1v for 2000s

카테고리

도움말 센터File Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기

질문:

2013년 4월 30일

답변:

2019년 10월 2일

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