I am trying to model a particle bouncing around in a box. The size of the box is 0<=x<=1 and 0<=y<=1. so given an initial position and velocity the particle will move until it hits a wall and then it bounces. I have an idea of how this should work but as I was working through the project I hit this problem. This is a simplified version of the code that is causing the problem. the value of x is 1 at some point in the iteration but the if statement doesnt recognmize it.
x = 0.5;
for i=1:6
x = x+0.1
if x == 1
disp('yes')
end
end

답변 (2개)

KALYAN ACHARJYA
KALYAN ACHARJYA 2021년 2월 9일
편집: KALYAN ACHARJYA 2021년 2월 9일

0 개 추천

It's because floating point numbers representation (Exactly). Hence If you're trying to do logical comparision (==) with floating-point numbers, be careful.
Please refer the following
More:
But if you are insisted to way out, you may consider difference between the numbers as allowable tolerance (error) and use > or < logical comparision in the "if statement".
Hope it Helps!
randerss simil
randerss simil 2021년 2월 9일

0 개 추천

%if true
x = 0.5;
for i=1:6
x = (x)+0.1
if strcmp(num2str(x),'1')
disp('yes')
end
end
Try the above

댓글 수: 1

Jan
Jan 2021년 2월 9일
Letting strcmp perform a rounding is a very indirect and instable way. The actual poblem of floating point number is not addressed here. Using a limit for the numeric comparison is better: if abs(x - 1) < 10 * eps

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2021년 2월 9일

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