Solving symbolic equation using solve
조회 수: 7 (최근 30일)
이전 댓글 표시
Hi,
I am trying to minimize the value of phi here. I want the values of E for which phi becomes zero but the code is not providing any solution, also there is some problem in the execution of solve function.
Can someone please help with the proper function to be used here for minimization.
b = [(5/60) (10/60) ];
syms E xfun Ifun phi phidiff
xfun = sym(zeros(10,2));
Ifun = sym(zeros(10,2));
phi = sym(zeros(10,2));
phidiff = sym(zeros(10,1));
E_Vyas = zeros(10,1);
for prog = 1:1:2
for conv = 1:1:10
xfun(conv,prog) = -(E)./(8.314.*T(conv,prog)); %here T is temperature file(10 by 2 matrix)
Ifun(conv,prog) = (T(conv,prog).*exp(xfun(conv,prog)))-(Eiget(-xfun(conv,prog))./8.314);
end
end
for conv = 1:1:10
phi(conv) = (Ifun(conv,1).*b(2))./(Ifun(conv,2).*b(1)) + (Ifun(conv,2).*b(1))./(Ifun(conv,1).*b(2));
phidiff = diff(phi,E);
E_Vyas(conv) = (real(solve(phidiff,E)))/1000;
conv;
show = E_Vyas(conv);
end
E_Vyas = smooth(E_Vyas,0.1,'loess');
function [Eix] = Eiget(xfun) %function for approximation for I(E,T)
A = log((0.56146./xfun)+0.65).*(1+xfun);
B = (xfun.^4).*(exp(7.7*xfun)).*((2+xfun).^3.7);
Eix= (((A.^-7.7)+B).^-0.13)-((exp(-xfun))./xfun);
end
댓글 수: 0
채택된 답변
Walter Roberson
2021년 2월 9일
b = [(5/60) (10/60) ];
syms E xfun Ifun phi phidiff
xfun = sym(zeros(10,2));
Ifun = sym(zeros(10,2));
phi = sym(zeros(10,1));
phidiff = sym(zeros(10,1));
E_Vyas = zeros(10,1);
for prog = 1:1:2
for conv = 1:1:10
xfun(conv,prog) = -(E)./(8.314.*T(conv,prog)); %here T is temperature file(10 by 2 matrix)
Ifun(conv,prog) = (T(conv,prog).*exp(xfun(conv,prog)))-(Eiget(-xfun(conv,prog))./8.314);
end
end
guess = sym('1.0');
for conv = 1:1:10
phi(conv) = (Ifun(conv,1).*b(2))./(Ifun(conv,2).*b(1)) + (Ifun(conv,2).*b(1))./(Ifun(conv,1).*b(2));
phidiff(conv) = diff(phi(conv),E);
tic
sol = vpasolve(phidiff(conv),E,guess);
toc
if isempty(sol)
E_Vyas(conv) = nan;
else
E_Vyas(conv) = real(sol)/1000;
guess = sol;
end
end
E_Vyas_smooth = smooth(E_Vyas,0.1,'loess');
function [Eix] = Eiget(xfun) %function for approximation for I(E,T)
A = log((0.56146./xfun)+0.65).*(1+xfun);
B = (xfun.^4).*(exp(7.7*xfun)).*((2+xfun).^3.7);
Eix= (((A.^-7.7)+B).^-0.13)-((exp(-xfun))./xfun);
end
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Calculus에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!