Iteration without any loop.
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I am working on B-spline, this code is to get a matrix as an output.
function [M] = Iterations(N) % N is an input variable
I=eye(N+1);M=zeros(N+1,N+1); % I is a diagnal matrix and M is inicially a zero matrix
for i=0:N/2 % interations
n=i:N-i;
b=(-1).^(N-n-i).*factorial(N-i)./factorial(n)./factorial(N-n-i).*(factorial(N)./factorial(N-i)./factorial(i));
M(i+1,i+1:N+1-i)=b;
end
M = rot90(fliplr(M),1)+M-diag(M).*I; % Output matrix
end
Ans
M =
-1 3 -3 1
3 -6 3 0
-3 3 0 0
1 0 0 0
I was wondering is there anyway i can remove a loop from inside the function here?
답변 (2개)
[M] = Iterations(3)
function [M] = Iterations(N) % N is an input variable
I=eye(N+1);M=zeros(N+1,N+1); % I is a diagnal matrix and M is inicially a zero matrix
i=0:N/2; % interations
n=(0:N).';
b = (-1).^(N-n-i).*gamma(N-i+1)./factorial(n)./gamma(N-n-i+1).*(factorial(N)./gamma(N-i+1)./factorial(i));
M = [tril(b).'; zeros(size(b.'))];
M = rot90(fliplr(M),1)+M-diag(M).*I;
end
댓글 수: 1
Jan
2021년 2월 5일
This fails for even N:
Matrix dimensions must agree.
Error in kjh>Iterations_4 (line 84)
M = rot90(fliplr(M),1)+M-diag(M).*I;
Why do you want to do this without a loop? When the purpose is an acceleration, omit the expensive factorial and power operations at first:
function M = Iterations(N)
F = [1, cumprod(1:21)]; % Emulated factorial()
sF = F;
sF(2:2:22) = -sF(2:2:22); % Include expensive power operation -1^(N-n-i)
FN = F(N+1);
M = zeros(N+1, N+1);
for i = 0:N/2
t = N - i + 1;
b = F(t) ./ F(i+1:t) ./ sF(t-i:-1:1) .* (FN ./ F(t) ./ F(i+1));
M(i+1, i+1:t) = b;
M(i+1:t, i+1) = b;
end
end
For N = 10 this is needs 16% of the runtime of the original.
But due to the factorial the output will be accurate for N <= 21. If you need such a small set of inputs only, it would be more efficient, to create a list of possible values once and store it in a persistent varibale.
function M = IterationsX(N)
persistent List
if isempty(List)
List = cell(1, 21);
for k = 1:21
List{k} = Iterations(k);
end
end
M = List{N};
end
댓글 수: 7
hyder abedi
2021년 2월 5일
Image Analyst
2021년 2월 5일
You can use tic and toc to measure elasped seconds.
For loops are not always slow. How big is your N? Unless your N is like hundreds of millions, I doubt the loop will take more than a fraction of a second. For N = 10 or 21, you're looking at an elapsed time of like microseconds.
hyder abedi
2021년 2월 5일
Jan
2021년 2월 5일
factorial(100) is 9.3e157. BSplines with so many points cannot be calculated accurately anymore, because the double values contain the first 16 digits only.
Walter Roberson
2021년 2월 5일
When you have factorial divided by factorial, consider using pochhammer; https://www.mathworks.com/help/symbolic/pochhammer.html
hyder abedi
2021년 2월 5일
hyder abedi
2021년 2월 5일
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