필터 지우기
필터 지우기

Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 10-by-10. not sure why i am getting this error

조회 수: 1 (최근 30일)
data_rho = [7840,0.44];
data_Cp = [490,0.0733333];
data_k = [13.1947,0.0126919];
%% Geometry
L = 0.03;
%% Boundary conditions
T0 = 1000;
Tinfinity = 20 + 273;
htc_top = 50;
htc_sides = 100;
htc_btm = 20;
Emissivity = 0.0;
time = 0;
%% thermocouple positions
tpx = [0.015 0.027 0.027];
tpy = [0.015 0.015 0.027];
%% Simulation control
n = 10;
CFL = 0.5;
itPlot = 10;
%% Discretize space
dx = L/(n-1);
x = 0:dx:L;
y = L:-dx:0; % T(1,1) is the top left
%% Initialize variables
T = ones(n,n)*T0;
T_new = zeros(n,n);
dtMat = zeros(n,n);
it = 0;
%% Physical constants
stefan = 5.670367e-8;
%% Record predictions
Temp_thermocouples = interp2(x,y,T,tpx,tpy);
SaveNumber = 1;
TimeVector(SaveNumber) = time;
TempSavedMatrix(SaveNumber,:) = Temp_thermocouples;
%% Model calculation
while max(max(T)) > 300 + 273.15
%% Thermophysical properties
rho = data_rho(1) + data_rho(2)*T;
k0 = data_k(1) + data_k(2)*T;
Cp = data_Cp(1) + data_Cp(2)*T;
%% Calculate temperature dependent parameters
alpha = k0./rho./Cp;
Br = stefan*Emissivity*dx./k0;
Biot_top = htc_top*dx./k0;
Biot_btm = htc_btm*dx./k0;
Biot_sides = htc_sides*dx./k0;
%% time step
for i = 2: n-1
for j = 2: n-1
dtMat(i,j) = CFL*dx*dx/4./alpha(i,j);
end
end
% top left
dtMat(1,1) = CFL*dx*dx/2./alpha(1,1)*(Biot_sides(1,1)+Biot_top(1,1)+2*Br(1,1)*T(1,1)^3);
% top edge
for j = 2: n-1
dtMat(1,j) = CFL*dx*dx/2./alpha(1,j)*(2+Biot_top+Br(1,j)*T(1,j)^3);
end
line with the error code is
for j = 2: n-1
dtMat(1,j) = CFL*dx*dx/2./alpha(1,j)*(2+Biot_top+Br(1,j)*T(1,j)^3);
end

채택된 답변

Daniel Pollard
Daniel Pollard 2021년 2월 4일
편집: Daniel Pollard 2021년 2월 4일
Biot_top is size 10x10. dtMat(1,j) is size 1x1. This means the LHS of your line is 1x1, and the RHS is 10x10, so you can't make the assignment.
I suspect you intended to write Biot_top(1,j)?

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Simulink에 대해 자세히 알아보기

태그

제품


릴리스

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by