Match numbers with letters

조회 수: 1(최근 30일)
Pax Azx
Pax Azx 2021년 1월 29일
댓글: Mathieu NOE 2021년 2월 1일
I need to find the name score of the names in a text file.
name point: David --> 4 1 22 9 4 = 4+1+22+9+4 = 40
Thanks for your help.
  댓글 수: 2
Philippe Lebel
Philippe Lebel 2021년 1월 29일
as there are many solutions posted that answer your question, i'd suggest to mark your question as answered.

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채택된 답변

Mathieu NOE
Mathieu NOE 2021년 1월 29일
this code does the trick :
ascii_value = uint32(yourstring); % convert your char / string into corresponding ASCII value
% let's converts ASCII values into values ranging from 1 to 26 (use offsets)
% uppercase letters
ind = find(ascii_value<91);
UL = ascii_value(ind) - 64;
% lowercase letters
ind = find(ascii_value>96);
LL = ascii_value(ind) - 96;
value = sum(UL) + sum(LL); %
  댓글 수: 4
Pax Azx
Pax Azx 2021년 1월 29일
I wrote to you. Thank you if you help.

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추가 답변(2개)

Jan 2021년 1월 29일
편집: Jan 2021년 1월 31일
Name = 'David';
Num = lower(Name) - 'a' + 1; % 'a' -> 1, 'b' -> 2, ...
Score = sum(Num);
[EDITED] You mention in comments, that you want to do this for "names in a text file". Do the files contain one name per line?
Str = fileread('YourTextFile.txt');
Str(Str == char(13)) = [];
CStr = strsplit(Str, char(10));
Score = zeros(size(CStr));
for k = 1:numel(CStr)
Score(k) = sum(lower(CStr{k}) - 'a' + 1);
  댓글 수: 4
Mathieu NOE
Mathieu NOE 2021년 2월 1일
@Jan : tx for your nice comments , but I'm not yet to your level - still I like to see how tricky problems can be solved elegantly by knowledgable people like you and others contributors here.

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Philippe Lebel
Philippe Lebel 2021년 1월 29일
im late to the show, but here we go anyway...
name = 'david';
a = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
total = 0;
for i=1:length(name)
arr = cellfun(@(x)isequal(x,name(i)),a);
[row,col] = find(arr);
total = total + col

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