Performing what toeplitz does without using pre-installed function

I currently have 8x8 matrix of NaNs. The assignment is to replace all elements of the NaN with numbers 1-8 and then flip them around the way toeplitz function would, without actually using it. We are supposed to use nested for loops and end up with this result:

1 2 3 4 5 6 7 8

2 1 2 3 4 5 6 7

3 2 1 2 3 4 5 6

4 3 2 1 2 3 4 5

5 4 3 2 1 2 3 4

6 5 4 3 2 1 2 3

7 6 5 4 3 2 1 2

8 7 6 5 4 3 2 1

Any idea how to do this? I am completely stuck. So far I only have this

toeplitzSize=8

toeplitz=nan(toeplitzSize)

for a=1:toeplitzSize

for b=1:toeplitzSize

if isnan(toeplitz(a,b))

toeplitz(a,b)= b;

end

end

end

[Stephen23]

Note that you should NOT name any variable toeplitz, as this shadows the inbuilt function.

Answer 1

[Sindhu Karri]

Hiii Losoupbowla,

Hope the below attached code helps

 
toeplitSize=8;
toeplitz=nan(toeplitSize);
for i=1:toeplitSize
   
    k=i;
    for j=1:toeplitSize
         if isnan(toeplitz(i,j))
     if(j<=i)
        toeplitz(i,j)=k;
        k=k-1;
        
        else
            toeplitz(i,j)=j-i+1; 
    end
         end  
    end
end

[Losoupbowla]

Thanks a lot!