function [temperature] = findSpinodal(x2,omegaSolid)
[temperature,eval] = fsolve(@(temperature) x2-(x2)^2-1.9858775*temperature/(2*omegaSolid),650);
[temperature,eval] = fsolve(@(temperature) x2-(x2)^2-1.9858775*temperature/(2*omegaSolid),450);
end
is this mean "solve @(temparture) brrbrbrbrbrr starting from 650"
then why they're use eval in [temparture, eval] ^^; so hard

 채택된 답변

Walter Roberson
Walter Roberson 2021년 1월 28일
편집: Walter Roberson 2021년 1월 28일

0 개 추천

yes it does mean to try to find the temperature that makes the expression 0 and to start at 650.
However, you should just rewrite and solve directly.
x2-(x2)^2-1.9858775*temperature/(2*omegaSolid) == 0
x2-(x2)^2 == 1.9858775*temperature/(2*omegaSolid)
(x2-(x2)^2)*(2*omegaSolid) == 1.9858775*temperature
and so temperature is the left side divided by the 1.98 constant. No need to search.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Symbolic Math Toolbox에 대해 자세히 알아보기

질문:

2021년 1월 28일

편집:

2021년 1월 28일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by