pid for dynamic malaria

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af af
af af 2021년 1월 21일
답변: Sam Chak 2022년 8월 20일
Can the pid controller be set to malaria dynamics?
  댓글 수: 7
af af
af af 2021년 1월 24일
i put [T,Y]=ode45(@malariaSEIRS,tspan,y0);
but it still gives an error
Walter Roberson
Walter Roberson 2021년 1월 24일
You appear to have functions named u1 and u2 and u3 that each take t as a parameter, but you have not posted the code for those functions.

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답변 (1개)

Sam Chak
Sam Chak 2022년 8월 20일
Not sure what are PID controllers for the Malaria dynamics. However, by the mathematical manipulation, you can probably propose as shown below to keep the disease spread under control.
tspan = [0 10];
y0 = zeros(1, 7);
[T, Y] = ode45(@malariaSEIRS, tspan, y0);
plot(T, Y), grid, xlabel('Days')
legend('S_h', 'E_h', 'I_h', 'R_h', 'S_v', 'E_v', 'I_v', 'location', 'East')
Y(end, :)
ans = 1×7
0.0001 1.5163 0.4067 0.0021 0.9990 125.2982 0.8853
function dydt = malariaSEIRS(t, y)
dydt = zeros(7, 1);
% parameters
phi = 0.502;
epsilon = 0.2;
beta = 0.8333;
landa = 0.09;
muh = 0.00004;
muv = 0.1429;
k = 0.7902;
a1 = 1/17;
a2 = 1/18;
lambdah = 0.2;
lambdav = 1000;
tau = 0.01 - 0.7;
psi = 0.05;
b = 0.005;
p = 0.25;
Sh = 1100;
Eh = 200;
Ih = 400;
Rh = 0;
Sv = 800;
Ev = 250;
Iv = 80;
Nh = Sh + Eh + Ih + Rh;
% Nv = Sv + Ev + Iv;
betam = beta*epsilon*phi*Iv/Nh;
landav = landa*epsilon*phi*Ih/Nh;
% states
Sh = y(1);
Eh = y(2);
Ih = y(3);
Rh = y(4);
Sv = y(5);
Ev = y(6);
Iv = y(7);
% u1, u2, u3
k3 = 1; % adjust this parameter
u3 = ((k3 - muv)*Iv + a2*Ev)/p;
u2 = 0;
k1 = 1; % adjust this parameter
u1 = (- (k1 - p*u3 - muv - 1*landav)*Sv - lambdav)/landav;
% Malaria dynamics
dydt(1) = lambdah + (k*Rh) - (1 - u1)*betam*Sh - muh*Sh;
dydt(2) = (1 - u1)*betam*Sh - (a1 + muh)*Eh;
dydt(3) = a1*Eh - (b + tau*u2)*Ih - (psi + muh)*Ih;
dydt(4) = (b + tau*u2)*Ih - (k + muh)*Rh;
dydt(5) = lambdav - (1 - u1)*landav*Sv - p*u3*Sv - muv*Sv;
dydt(6) = (1 - u1)*landav*Sv - p*u3*Ev - (a2 + muv)*Ev;
dydt(7) = a2*Ev - p*u3*Iv - muv*Iv;
end

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