'setprecision', 24

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Beat Aebischer
Beat Aebischer 2021년 1월 21일
댓글: Beat Aebischer 2021년 1월 26일
Why are the two results below the same? I would like to simulate single precision with system_dependent('setprecision' , 24).
>> system_dependent('setprecision', 64)
>> 10000*sqrt(exp(pi))-48104
ans =
0.773809653510398
>> system_dependent('setprecision', 24)
>> 10000*sqrt(exp(pi))-48104
ans =
0.773809653510398

채택된 답변

Walter Roberson
Walter Roberson 2021년 1월 25일
system_dependent('setprecision')... I seem to recall that it only ever had effect on windows and only for some of the older releases. You could find more information on Yair's undocumented-matlab site.
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Beat Aebischer
Beat Aebischer 2021년 1월 26일
Thanks. This means one cannot rely on 'system_depedent' or 'feature'. Anyway in the ML version I currently use (9.5.0), 'setprecision' does not seem to work - it is also asking a lot as it would have to be "system independent".
Instead I have tried casting the input with the command 'single', this seems to work.

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추가 답변(1개)

Gaurav Garg
Gaurav Garg 2021년 1월 25일
Hi,
On running the same code, and then verifying the variable precision being used, I could see that the variable precision was never changed.
You can verify the variable precision using the digits.
digits
In your case, if you need to change the precision, you can use the below piece of code -
digitsOld = digits(64);
vpa(10000*sqrt(exp(pi))-48104)
digits
digitsOld = digits(24);
vpa(10000*sqrt(exp(pi))-48104)
digits
You can also follow the documentation here.
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Walter Roberson
Walter Roberson 2021년 1월 25일
The solution with vpa needs modification to prevent the argument from being evaluated in double precision before it gets to vpa.
Q = @(v) sym(v) ;
digitsOld = digits(64);
vpa(10000*sqrt(exp(Q(pi)))-48104)
digits
digitsOld = digits(24);
vpa(10000*sqrt(exp(Q(pi)))-48104)
It would need further modifications to emulate step by step evaluation at the chosen digits the way that setting system_dependent('precision') would

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