Creating matric of multiple arrays
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x=0:12;
k=5;
a=k+x;
b=k+2x;
c=k+4x;
d=kx;
I'd like to create 2*2 matrix of four arrays (a,b,c,d).
Z=[a b; c d];
How could I realize this task by using for loop? Or do you have any other way to realize it? I ask for your advice! Thank you in advance!
채택된 답변
Bob Thompson
2021년 1월 20일
You should be able to accomplish what you're looking for with some matrix indexing, no loop necessary.
x = 1:100;
k = 12;
a = x + k; % Makes a 100x1 size array, 13:112
b = 2*x + k; % Makes a 100x1 size array following the same formula
c = 4*x + k;
d = x * k;
% Adding a third dimension of Z allows you to basically stack each of the elements of a, b, c, and d
% into the one 2x2 format. Z(:,:,1) is a 2x2 of [a(1), b(1); c(1), d(1)], and each subsequent 'sheet'
% takes you to the next set of elements in the four matrices.
Z(1,1,:) = a;
Z(1,2,:) = b;
Z(2,1,:) = c;
Z(2,2,:) = d;
추가 답변(1개)
Adam Danz
2021년 1월 20일
편집: Adam Danz
2021년 1월 20일
Perhaps this (scroll down to see vectorized version)?
x=0:12;
k=5;
a=k+x;
b=k+2*x;
c=k+4*x;
d=k*x;
Z = nan(2,2,numel(x));
for i = 1:numel(x)
Z(:,:,i) = [a(i) b(i); c(i) d(i)];
end
disp(Z)
If so, you don't need a loop.
Z = reshape([a;c;b;d],2,2,numel(x)) % Assuming a,b,c,d are row vectors
댓글 수: 2
Adam Danz
2021년 1월 20일
No problem, I'm glad you found solutions!
For what it's worth, the reshape solution is most efficient and only requires 1 line.
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