Converting a 3D Matrix to multiple 2D matrices

I have a 3D matrix, 1000 x 1000 x 40
I want to convert this matrix to 40 different matrices, 1000 x 1000 each. I suppose I am asking for the inverse of repmat, however searches into that have not led to progress.
Any help is appreciated.

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Something like this?
largeMatrix = randn(1000,1000,40);
smallMatrixArray = cell(40,1);
for iOuterDim = 1:40
smallMatrixArray{iOuterDim} = largeMatrix(:,:,iOuterDim);
end
I want to convert this matrix to 40 different matrices
Why? What benefit do you hope to gain by doing that instead of indexing into the array to retrieve the appropriate slice when needed?
A = reshape(1:(3*4*5), [3 4 5]);
A4 = A(:, :, 4)
A4 = 3×4
37 40 43 46 38 41 44 47 39 42 45 48
What happens when or if you expand your problem sizes to an array of size 10000 in the third dimension? Your workspace would become awfully cluttered with ten thousand and one arrays in it.

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Bruno Luong
Bruno Luong 2021년 1월 17일
편집: Bruno Luong 2021년 1월 17일

1 개 추천

Assuming A is array 1000 x 1000 x 40
C = num2cell(A,[1 2]);

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You'll have to write
C = shiftdim(num2cell(A,[1 2]));
to get rid of the leading singleton dimensions, though.
Well it is nicer but it is not requirement by OP.
C{k} still give the the kth matrix as requested.

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2021년 1월 17일

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2021년 1월 17일

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