changing the name of multiple csv files in a folder

조회 수: 13(최근 30일)
C.G. 2021년 1월 15일
댓글: Stephen 2021년 1월 15일
I have a folder containing 3000 csv files. All of these are named in the format: cor0.1 sc10 fc0.1_0.csv.
I want to change the name of all of these files to c0_1f0_1_0.csv.
Is there a way i can write a loop to do this for me?

채택된 답변

Mathieu NOE
Mathieu NOE 2021년 1월 15일
this is a first attempt
I prefered to create the renamed copies in a separate folder
also my code will probably need some upgrade as I don't know how the numberring inside your filenames can evolve among your 3000 files
d = dir('*.csv')
dir_out = [cd '\out']
for ci = 1:numel(d)
filename = d(ci).name;
ind_und = strfind(filename,'_'); % search underscores
ind_dot = strfind(filename,'.'); % search dots
ind_f = strfind(filename,'f'); % search "f"
new_filename = [filename(1) filename(ind_dot(1)-1) '_' filename(ind_dot(1)+1) filename(ind_f ),...
filename(ind_dot(2)-1) '_' filename(ind_dot(2)+1) '_' filename(end-4:end)];
  댓글 수: 9
Stephen 2021년 1월 15일
Rather than fragile indexing, it better to use fileparts to split the filename and file extension:

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추가 답변(1개)

Matt Gaidica
Matt Gaidica 2021년 1월 15일
편집: Matt Gaidica 2021년 1월 15일
csvPath = '/path/to/files';
filelist = dir(fullfile(csvPath,'*.csv'));
for iFile = 1:numel(fileList)
thisFile = fullfile(csvPath,fileList(iFile).name);
movefile(thisFile, strrep(thisFile,'old','new'));
This is just psuedocode. I don't quite see how you're mapping the old filename to the new one, so I just placed a string replace function in the loop. If you need help on that piece, please post more details.
  댓글 수: 6
C.G. 2021년 1월 15일
I understand sprintf, but i am struggling to write a loop to do this.
I have started using Mathieu's code below, but this reaches 10 iterations and stops even though it identifies 3001 csv's

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