data fitting by Integration with variable limit with a unknown parameter.

I want to fit experimental data with equation:
y = C(1) * 74.826 * (x/T(1))^3 * integration (t^4*exp(t)/(exp(t)-1)^2), 0, T(1)/x) + C(2) * 24.942 * (T(2)/x)^2 * exp(T(2)/x)/(exp(T(2)/x)-1)^2 + C(3) * 24.942 * (T(3)/x)^2 * *exp(T(3)/x)/(exp(T(3)/x)-1)^2
with six unknown parameters: C(1), T(1), C(2), T(2), C(3), T(3).
The integral part is giving error all times. How to write the programm please help.
Thank you.

 채택된 답변

You can do something like this:
y_fcn = @(CT,x) CT(1) * 74.826 * (x./CT(4)).^3 * integral(t.^4.*exp(t)./(exp(t)-1).^2), 0, CT(4)./x) + ...
CT(2) * 24.942 * (CT(5)./x).^2 .* exp(CT(5)./x)./(exp(CT(5)./x)-1).^2 + CT(3)*24.942*(CT(6)./x).^2.*exp(CT(6)./x)./(exp(CT(6)./x)-1).^2;
err_fcn = @(CT,x,y) sum((y-y_fcn(CT,x)).^2);
CT0 = [1 2 3 4 5 7]; % Some sensible initial guess for C and T, that we concatenate together as CT = [C,T]
CT_best = fminsearch(@(CT) err_fcn(CT,x_obs,y_obs),CT0)
You most likely have to use element-wise operations in the equation for y (I might have missed one or two multiplictions or power-operations). Then it should be fine to use ordinary least-square fitting of the C and T parameters (provided you have enough data-points, and they have the same standard deviation - but I expect you to know this already).
HTH

댓글 수: 5

OK, I realise that I goofed in the definition of y_fcn - twice, the first fix you'll have to do is to make the first input argument to integral into a function, something like this:
y_fcn = @(CT,x) CT(1) * 74.826 * (x./CT(4)).^3 * integral(@(t) t.^4.*exp(t)./(exp(t)-1).^2, 0, CT(4)./x) + ...
CT(2) * 24.942 * (CT(5)./x).^2 .* exp(CT(5)./x)./(exp(CT(5)./x)-1).^2 + ...
CT(3)*24.942*(CT(6)./x).^2.*exp(CT(6)./x)./(exp(CT(6)./x)-1).^2;
note the "@(t) expression" - that is a definition of a anonymous function/dynamic function. The next problem is that your upper bound is now an array of values - that will also cause an error - exactly how to fix that I do not know since it is not clear what you want that expression to return - a single value of the integral from 0 to T(1)/x(end) or an array of the integrals from 0 to T(1)/x(1), from 0 to T(1)/x(2), ... from 0 to T(1)/x(end)?
First you have to clarify that.
integral will return : an array of the integrals from 0 to T(1)/x(1), from 0 to T(1)/x(2), ... from 0 to T(1)/x(end).
error:
Unrecognized function or variable 'x_obs'.
Error in test12>@(CT)err_fcn(CT,x_obs,y_obs) (line 40)
CT_best = fminsearch(@(CT) err_fcn(CT,x_obs,y_obs),CT0);
Error in fminsearch (line 200)
fv(:,1) = funfcn(x,varargin{:});
Error in test12 (line 40)
CT_best = fminsearch(@(CT) err_fcn(CT,x_obs,y_obs),CT0);
and guess values are CT0 : [CT1 = 1, CT4 = 300, CT2 = 5, CT3 = 150, CT5 = 9, CT = 250]. Is this x_obs is x? means data at x-axis?
OK, we have 2 steps to fix.
1, the integral function only returns a value to an integral between 2 points, corresponding to the functions trapz and sum. Those two functions have cummulative variants, cumtrapz and cumsum, unfortunately integral has no such built-in-variant. However, I had a problem similar to yours and wrapped the calculations into a simple cumintegral-function. It is attached, and you should be able to replace "integral" with "cumintegral" in the definition of y_fcn:
y_fcn = @(CT,x) CT(1) * 74.826 * (x./CT(4)).^3 .* cumintegral(@(t) t.^4.*exp(t)./(exp(t)-1).^2, 0, CT(4)./x) + ...
CT(2) * 24.942 * (CT(5)./x).^2 .* exp(CT(5)./x)./(exp(CT(5)./x)-1).^2 + ...
CT(3)*24.942*(CT(6)./x).^2.*exp(CT(6)./x)./(exp(CT(6)./x)-1).^2;
Note that we have to change the matrix-multipy before cumintegral to a element-multiply.
2, In the call to fminsearch we use the dynamic anonymous-function capability to define a name-less function that is only a variable of 1 variable, CT, the other two inputs to err_fcn are taken at their values at the time of the call, in my code-snippet I named them x_obs and y_obs, those should be your x and y:
CT_best = fminsearch(@(CT) err_fcn(CT,x,y),CT0)
These modifications will give you something that returns a result. You might have to check that your y_fcn-function is a function that does what you expect it to.
The equation is:
P = P0 + 4RC*(T/C)^5* integration (0, (C/T)) (x^5/(exp(x)-1)*(1-exp(-x))) dx
P0, R and C are constants.
With given values of P and T, finding these constants.
program in matlab for this :
Tv = linspace(200, 300, 10).'; % vector of T values
Pv = Tv.^2; % vector of P values
P_mdl = @(P0, R, C, TT) arrayfun(@(T) P0 + 4*R.*C.*(T/C).^5 * integral(@(x) x.^5./(exp(x)-1).*(1-exp(-x)), 0, (C/T)), TT);
sol = lsqcurvefit(@(param, T) P_mdl(param(1), param(2), param(3), T), rand(3,1), Tv, Pv);
P0_sol = sol(1);
R_sol = sol(2);
C_sol = sol(3);
This is same variable uper limit integration case but what are these Tv and Pv ? please help me to write program in this lsqcurvefit.
That cumintegral is also not giving the results. cumintegral is coming as undefined variable.
Ah, I forgot to attach the cumintegral function. Here it is...

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Applications에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by