naming using a string function

Hello everyone,

I have let's say : x=' a name' ; and B= [1 2 3],

and I want to create a variable ' a name' = B whiche is [1 2 3], in another word i want to create a variable using the string of another variable (example filename='Hallo' the 'Hallo'= B=[1 2 3],

So, I tried to use [x]=B; but it does not work;

[Stephen23]

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

Is there a particular reason why you need to magically define variable names?

Usually when beginners ask about this topic it is because of this:

https://xyproblem.info

https://en.wikipedia.org/wiki/XY_problem

Given that your own example ' a name' is an invalid variable name, is there any particular reason why you want to force yourself into writing slow, complex, fragile, obfuscated code that is difficult to debug?

[Ayman Mounir]

actually, I read many csv data and concantae them in one matlab table then i have to save as the specfic name :

for example: dir()

all_table=[] % concatenate all csv files

for i=1:numel(files);

R= readtable((files(i).name));

all_table=[all_table;R];

save (all_table, 'standard_name') % mast save as mat file because i exceeded 2^20 ( the limit of exporting an excel file) but this command does not include an option to save the file with desired name.

:D

[Stephen23]

@Ayman Mounir: your save usage makes no sense.

The first input argument of save must be a filename, so why are you providing a table as the first input?

The second input is usually the name of the variable to be saved, it is not clear what you expect the character vector 'standard_name' to achieve. I recommend that you read the save documentation, it explains how to use save.

In any case, magically defing variable names is unlikely to be a suitable solution to ... whatever you problem might be.

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

Answer 1

[Catalytic]

s.(x)=B

[Ayman Mounir]

thanks, but without creating a structure

Answer 2

[Stephen23]

The MATLAB approach:

N = numel(files);
C = cell(1,N);
for k = 1:N
    F = fullfile(files(k).folder,files(k).name);
    C{k} = readtable(F);
end
dataname = vertcat(C{:});
save('some_file_name.mat', 'dataname')