How to solve "index exceeds the number of array elements"

조회 수: 1 (최근 30일)
Ryan Majid
Ryan Majid 2020년 12월 24일
댓글: Ryan Majid 2020년 12월 24일
Hi,
Why I can't plot the following code? The error is: Index exceeds the number of array elements (1).
What I'm trying to achive is that a user enters a scalar value f (such as 1500) anf Ht and Hr. So, I want to find value of ahr and L accondingliy and then plot L vs f. SO on f axis I shoud have 100,150,200,250,300,....,1500 and corrsponding values on L axis.
for i=100:50:f
cm=0;
ahr(i)=(1.1*log10(f(i))-0.7)*Hr-1.56*log10(f(i))-0.8;
L(i)=46.3+33.9*log10(f(i))-13.82*log10(Ht)-ahr+(44.9-6.55*log10(Hr))*log10(d)+cm;
plot(f,L)
end

채택된 답변

Mischa Kim
Mischa Kim 2020년 12월 24일
편집: Mischa Kim 2020년 12월 24일
Hi Ryan, try something like this:
fl = 100;
fu = 1500; % replace as necessary
N = 100;
f = linspace(fl,fu,N);
cm = 0;
for ii = 1:numel(f) % careful with "i", this is also the imaginary unit
ahr(ii) = (1.1*log10(f(ii))-0.7)*Hr-1.56*log10(f(ii))-0.8;
L(ii) = 46.3+33.9*log10(f(ii))-13.82*log10(Ht)-ahr(ii)+(44.9-6.55*log10(Hr))*log10(d)+cm;
end
plot(f,L)
  댓글 수: 3
Mischa Kim
Mischa Kim 2020년 12월 24일
편집: Mischa Kim 2020년 12월 24일
With
for i=100:50:f
i is assigned values: 100, 150, 200, 250, etc. As a result, in
L(ii) = 46.3+33.9*log10(...
you create a (rather long) vector L and assign values to L(100), L(150), and so on and so forth. At the same time, f is a scalar (just one number). For the plot() command to work f and L need to be vectors of the same size.
Ryan Majid
Ryan Majid 2020년 12월 24일
Understood. So appreciated.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Title에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by