Accessing values of fieldnames in a structure without using the fieldnames function
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I've got a structure which has 20 different field names, e.g. 'fieldname01','fieldname02' etc.
Each fieldname has a numeric value, such as:
fieldname01: 0.56 fieldname02: 0.93 fieldname03: -0.34
Up to fieldname20
I need to access the numeric values of certain field names, for example the 2nd, 5th and 15th. Just wondering what would be the right way about doing this without using the fieldnames function if that's possible at all?
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Sven 2013년 4월 4일
편집: Sven 2013년 4월 4일
S = struct('field1',1,'field2',2)
fieldStr = ['fields' num2str(1)]
Or, with your particular example:
for i = 1:20
val = S.(sprintf('fieldname%02d',i))
Please note however that the "right" way to store data from 1 to 20 isn't in a structure with the number built into the name. Instead it sounds like you should be using an array (or cell array if your datatypes are different).
myData = [12 10 3];
is much cleaner than:
myData.element1 = 12
myData.element2 = 10
myData.element3 = 3
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Jan 2013년 4월 4일
+1 for mentioning, that an enumeration of fieldnames is much worse than using arrays.
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