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parfor indexing and order

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xplore29
xplore29 2013년 4월 3일
[a,b,c]=size(Mask); % a=b=c=3;
parfor i=1:size(Mask,3)
i
end
I was expecting to see i=1,i=2,i=3 in a sequence as one would see in a for loop but it is giving me i=3,i=2,i=1 . This is in reverse order. I cant figure out the reason.

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xplore29
xplore29 2013년 4월 4일
Although I am not using parfor for variable display purpose but I am curious to know that if I try to display the variable like this in parfor the order will always be reverse (like in my example) or it can be random.

추가 답변 (1개)

Edric Ellis
Edric Ellis 2013년 4월 4일
PARFOR loops can run in parallel, and as such, the iterations might run in any order. You should not rely on this order. In particular, as you have observed, PARFOR starts running iterations in reverse order.

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