how can i convert an integer to an array in this function?
이전 댓글 표시
function a=get_array_num(n)
end
requirments:
1.no loops,if,recurion or logical operatos
2.no num2str or str2num
3.length_of(n)=number of digits in "n" (help function)
i think maybe logspace is useful here...but how?
댓글 수: 8
Walter Roberson
2013년 3월 31일
That does not define any return value "a".
The only way that you can meaningfully have length(n) be the same as the number of digits in n, is if n is a scalar value (length 1) with a single digit.
Zaza
2013년 3월 31일
Image Analyst
2013년 3월 31일
편집: Image Analyst
2013년 3월 31일
That would mean your "a" (now called "r") is an array of 1 - not really much of an array. Besides - that code uses recursion, which is not allowed.
Zaza
2013년 3월 31일
Walter Roberson
2013년 4월 1일
Why is length_of(0) 1 instead of 0? Why is length_of(-23) 1 instead of 3?
Zaza
2013년 4월 1일
Jan
2013년 4월 2일
For length_of() the log10 function would be much smarter.
답변 (1개)
Image Analyst
2013년 3월 31일
How about
a = zeros(n);
or
a = n * ones(1, 10);
or something similar? There is an infinite variety of arrays you could make that would full those requirements, though requirement #3 is not well explained at all (no idea what it even means).
댓글 수: 16
Walter Roberson
2013년 3월 31일
I see nothing in the requirements that the output must have any relationship to the input.
Image Analyst
2013년 3월 31일
True, so there are even more infinite ways to answer. This is so poorly described, even with additional comments, that I don't even know how to help anymore.
Walter Roberson
2013년 4월 1일
You have not indicated what the result of the function is to be.
Zaza
2013년 4월 1일
Image Analyst
2013년 4월 1일
strN = num2str(n) % Convert to string.
a = strN - '0' % Convert characters to separate numbers.
Walter Roberson
2013년 4월 1일
num2str() was prohibited in the assignment.
Image Analyst
2013년 4월 1일
What a stupid requirement. Then use sprintf() as the "loophole":
strN = sprintf('%d',n)
a = strN - '0'
Walter Roberson
2013년 4월 1일
Perhaps you should post the exact assignment.
Image Analyst
2013년 4월 1일
I did it in 5 lines with a for loop, rem(), floor(), and finally fliplr() to reverse the last digits.
- for
- call rem
- reassign n
- end
- call fliplr
I'm sure you don't want me to just give you the answer outright (because you could be considered as not doing your own work) so give that a try.
Walter Roberson
2013년 4월 1일
The requirements include 'no loops'
Image Analyst
2013년 4월 1일
Ha! I give up. Who wants to work like that? I hate it when they say to use MATLAB but don't let you use any of the power of it. I don't see the point. I don't see any way, off the top of my head, to march along the digits of your integer if you can't use strings, loops of any type, or recursion if your integer is of unknown length. Of course if you know it's always 4 digits, then you can just write the contents of the for loop 4 times. Good luck with it though. If something strikes me, I'll post a hint.
Walter Roberson
2013년 4월 1일
I can do it in one smallish line, once given the length_of function. Loops may have been prohibited but ":" has not been.
Zaza
2013년 4월 2일
Jan
2013년 4월 2일
@Zaza: It consumed some time and energy to bring you to post an explicit example. We get some parts of the problem distributed to the question and over several comments. Therefore an efficient answer is impossible.
Please edit the original question and insert all available information. Then show us, what you have tried so far, because of course we are not going to solve your homework: you couldn't submit it anymore without cheating!
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