what is wrong with this code?should i add instruction to declare X?
조회 수: 1 (최근 30일)
이전 댓글 표시
function X = sudoku(X)
% SUDOKU Solve Sudoku using recursive backtracking.
% sudoku(X), expects a 9-by-9 array X.
% Fill in all “singletons”.
% C is a cell array of candidate vectors for each cell.
% s is the first cell, if any, with one candidate.
% e is the first cell, if any, with no candidates.
[C,s,e] = candidates(X);
while ~isempty(s) && isempty(e)
X(s) = C{s};
[C,s,e] = candidates(X);
end
% Return for impossible puzzles.
if ~isempty(e)
return
end
% Recursive backtracking.
if any(X(:) == 0)
Y = X;
z = find(X(:) == 0,1); % The first unfilled cell.
for r = [C{z}] % Iterate over candidates.
X = Y;
X(z) = r; % Insert a tentative value.
X = sudoku(X); % Recursive call.
if all(X(:) > 0) % Found a solution.
return
end
end
end
% ------------------------------
function [C,s,e] = candidates(X)
C = cell(9,9);
tri = @(k) 3*ceil(k/3-1) + (1:3);
for j = 1:9
for i = 1:9
if X(i,j)==0
z = 1:9;
z(nonzeros(X(i,:))) = 0;
z(nonzeros(X(:,j))) = 0;
z(nonzeros(X(tri(i),tri(j)))) = 0;
C{i,j} = nonzeros(z)’;
end
end
end
L = cellfun(@length,C); % Number of candidates.
s = find(X==0 & L==1,1);
e = find(X==0 & L==0,1);
end % candidates
end % sudoku
댓글 수: 3
채택된 답변
the cyclist
2013년 3월 29일
It looks like you should be calling that function with the syntax
>> sudoku(X)
where X is a 9x9 array (which presumably represents the sudoku puzzle layout).
Is that what you are doing?
댓글 수: 4
Walter Roberson
2013년 3월 29일
Assign a 9 x 9 matrix of initial values to a variable, such as Puzzle1. Then at the command line,
sodoku(Puzzle1)
추가 답변 (0개)
참고 항목
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!