Finding closest value in data table

1) I want load large amount of experiment data (distance for x-axis, velocity for y-axis).

2) Find and load the closest to 1m on the x-axis, and also the corresponding the velocity in y-axis.

3) Find and load the closest to 2m on the x-axis, and also the corresponding the velocity in y-axis.

4) Find and load the closest to 3m on the x-axis, and also the corresponding the velocity in y-axis.

I want to rearrange the experiment data with regular intevals as above.

Please help..

x_distance	y_velocity
0.52299	0.000237
1.04598	0.041598
1.56897	0.005755
2.09196	0.012987
2.614949	0.009894
3.137939	0.050168
3.660929	0.00584
4.183919	0.045582
4.706909	0.00007
5.229899	0.054282
5.752889	0.002132
6.275879	2.508755
6.798868	3.193212
7.321858	3.460158
7.844848	3.206859
8.367838	2.923524
8.890828	2.23533
9.413818	1.127799
9.936808	0.429399
10.459798 0.814943

Answer 1

[KALYAN ACHARJYA]

Hints:

data=[0.52299	0.000237
1.04598	0.041598
1.56897	0.005755
2.09196	0.012987
2.614949	0.009894
3.137939	0.050168
3.660929	0.00584
4.183919	0.045582
4.706909	0.00007
5.229899	0.054282
5.752889	0.002132
6.275879	2.508755
6.798868	3.193212
7.321858	3.460158
7.844848	3.206859
8.367838	2.923524
8.890828	2.23533
9.413818	1.127799
9.936808	0.429399
10.459798   0.814943];

Next: Distance for x-axis, velocity for y-axis

x_distance=data(:,1);
y_velocity=data(:,2);

Next: "Find and load the closest to 1m on the x-axis, and also the corresponding the velocity in y-axis."

What does the 1m menas?

Is that closset between x_distance & y_velocity?? If so, then

close_1m=x_distance-y_velocity;

Then finding the correcponding index

idx=find(close_1m==min(close_1m))

If you are looking for finding close in between in the same array, then you can use diff function

Please do the rest part by yourself.

:)