필터 지우기
필터 지우기

4byte uint8 array to single uint32 value

조회 수: 81 (최근 30일)
Maximilian Becker
Maximilian Becker 2020년 12월 7일
댓글: Steven Lord 2023년 5월 25일
I have an uint8 array containing 4 elements each representing 1byte.
myArray = [0x32 0x45 0x56 0x81] % just an example
% looks like this: myArray(1)=8bit, myArray(2)=8bit, myArray(3)=8bit, myArray(4)=8bit]
I mainly need to extract all the 32 bits and combine them to one uint32 value:
myValue = 0x32455681
%should look like this 32bit: myArray(1)myArray(2)myArray(3)myArray(4)
The goal is basically to remove the array structure and chain all the 32bits together
I once came from such an uint32 number and used the rearrange and bitget function to crate this array structure, but I somehow don't see how to come back.
As an important requirement, all the used functions must be able to be generate to C code
Any ideas?

채택된 답변

Ameer Hamza
Ameer Hamza 2020년 12월 7일
편집: Ameer Hamza 2020년 12월 7일
You can use typecast()
myArray = [0x32 0x45 0x56 0x81];
out = swapbytes(typecast(myArray, 'uint32')); % swapbytes is needed on little-endian systems
Result
>> out
out =
uint32
843404929
>> dec2hex(out)
ans =
'32455681'
  댓글 수: 7
Nur Fatin Atirah Mohd Rawi
Nur Fatin Atirah Mohd Rawi 2023년 5월 25일
Do you know how to convert single uint 32 into uint 8?
Steven Lord
Steven Lord 2023년 5월 25일
format longg
x = randi([intmin('uint32') intmax('uint32')], 1)
x =
3159077208
y = typecast(x, 'uint8')
y = 1×8
0 0 0 43 118 137 231 65
format hex
x
x =
41e789762b000000
y
y = 1×8
00 00 00 2b 76 89 e7 41
swapbytes(x)
ans =
0000002b7689e741

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Logical에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by