Matrix dimensions must agree.

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vincenzo violi
vincenzo violi 2020년 12월 6일
댓글: vincenzo violi 2020년 12월 6일
Hello , I am new on Matlab and I am trying to find out what's going on here.
Basically the error is :
Matrix dimensions must agree.
Error in EdgeExe2 (line 54)
Tup(k)=Dn/W.*log(1+((Pr.*h)/sigma2)+(Texe));
Could someone help me to find out the reason? Really thanks
for k = 1:length(d1range)
d1 = d1range(k);
L= zeros(length(d1range));
Tupload = zeros(length(d1range));
L(k,:)=((lambda)./(4*pi*(d1range))).^2; %PATH-LOSS
Pr=Pt_w*Gt*Gr*L;
taps=10;
h=randn(1,taps)+j*randn(1,taps);
Tup(k)=Dn/W.*log(1+((Pr.*h)/sigma2)+(Texe));
Tupload(k,:) = Tup(k);
end

채택된 답변

Setsuna Yuuki.
Setsuna Yuuki. 2020년 12월 6일
편집: Setsuna Yuuki. 2020년 12월 6일
The arrays dimensions are differents
Dn/W.*log(1+((Pr.*h)/sigma2)+(Texe)) %Is a 10x10 complex matrix
If you use
Tup(k) %You are storing a variable
  댓글 수: 3
Setsuna Yuuki.
Setsuna Yuuki. 2020년 12월 6일
You can use Tup{k}. But it depend on what you need from this array
Tup{k}=Dn/W.*log(1+((Pr.*h)/sigma2)+(Texe));
Tupload = Tup{1,k};
vincenzo violi
vincenzo violi 2020년 12월 6일
I need to calculate this values and plot it. It's about latency calculation according distances variation. But I am stucked before the plot.
Unfortunatelly neither your solution actually really works. Matlab gives me back always same mistake. Anyway thanks the some for your time.

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