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Help in Syntax of Eval and Sprintf

조회 수: 5 (최근 30일)
ARS
ARS 2013년 3월 14일
Hi,
I want to run the following expression:
*X = fts2mat(ESP('01-Jan-97::31-Dec-2012'))*
The above statemement works fine. ESP is my financial time seris(fts) container. I am getting the desired results in X.
But now I wish the dates to be passed from a cell array of date strings I have as mydate1{} and mydate2{} in place of the datestrings given in the first statement. I think it can be done via
*eval(sprintf(fts2mat(ESP('mydate1''::''mydate2'))));*
But the above gives error.
Help will be highly appreciated.
Regards,
AMD.

채택된 답변

ChristianW
ChristianW 2013년 3월 14일
Y = cell(size(mydate1)); % preallocate
for k = 1:length(mydate1)
str = [mydate1{k} '::' mydate2{k}]; % Date String Range
% str = sprintf('%s::%s',mydate1{k},mydate2{k}); % Alternative
Y{k} = fts2mat(EPS(str)); % output saved in cell Y
end
  댓글 수: 2
ARS
ARS 2013년 3월 14일
Thanks a lot.
Can you please explain this: str = sprintf('%s::%s',mydate1{k},mydate2{k});
I mean why can't it be
str = sprintf(mydate1{k},'%s::%s',mydate2{k});
Is there any order to follow? like.,,the operator :: needs to be in the start? but it is evaluated in the middle actually.
Regards
AMD.
ChristianW
ChristianW 2013년 3월 14일
doc sprintf
An example:
sprintf('answer=%d',3) % ans = 'answer=3'
sprintf('%d is the answer',3) % ans = '3 is the answer'
The Symbol %d determines where the variable (3) is placed in the string. Same with %s, s announces that the variable is a string.
sprintf('answer=%s','HELLO')
sprintf('%s is the answer','HELLO')

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