Square Root Complex Numbers
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Hi
I'm new to Matlab. I have a matrix of data for example 1.04,-5.84,-5.84,8.54 etc. As you can see its a mixture of positive and negative values. I have to square root all the numbers and then add the square root up.
I get an output like this: 0 + 0.2572i 1.4758 0 + 1.0258i 0 + 1.0297i .... etc
How can I add these up because when I do the sum total is displayed like so: 24.1589 +25.8258i I was expecting a real number such as 25.0414 why is it formatted like this. I am new to matlab so not sure what I need to do, works fine if my data has no negative numbers so I assume it's to do with that.
Thanks
댓글 수: 3
Walter Roberson
2013년 3월 9일
Suppose your entire data was just (say) -2 . Then what would you want as the result of the operation?
Josh
2013년 3월 9일
Youssef Khmou
2013년 3월 9일
real parts are summed separately from imaginary parts , if you want add both Real and Imag sumsthen try :
r=rand(10);
p=sqrt(r);
S=sum(real(p(:)))+sum(imag(p(:)));
답변 (2개)
Youssef Khmou
2013년 3월 9일
hi Josh,
the square root of <0 number is complex number , if you only want the real part use "real" function, but if you want imaginary part, use "imag" function, and for the modulus you can use "abs" function , example :
r=randn(10);
p=sqrt(r);
Real_part=sum(real(p(:)));
Imag_part=sum(imag(p(:)));
Modul_part=sum(abs(p(:)));
Walter Roberson
2013년 3월 10일
편집: Walter Roberson
2013년 3월 10일
To get the results you indicate you want (which are not the results one would normally want when taking the square roots of negative numbers),
sum(sqrt(r(r>0))) - sum(sqrt(-r(r<0)))
Remember, sqrt(-A) is not -sqrt(A) but is instead 1i * sqrt(A) where 1i indicates sqrt(-1)
댓글 수: 5
Yogan Sganzerla
2019년 8월 6일
Dear Walter,
I have a matrix M with complex number, as u can see the image below.

I would like to know the correct way to extract the squere root of M.
Could I use sqrm(M)?
Thank you for your attention.
Torsten
2019년 8월 6일
You want to get the matrix A with A^2 = M or with A.^2 = M ?
Yogan Sganzerla
2019년 8월 6일
편집: Yogan Sganzerla
2019년 8월 6일
A^2 = M
Torsten
2019년 8월 6일
A = sqrtm(M)
Yogan Sganzerla
2019년 8월 6일
Perfect! Thank you very much.
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