How to find the last 1 in every row

Simliar to this question, but for finding the last 1 in each row.

Say I have a matrix

A = [0 1 1 1 0;
     1 1 1 0 0;
     0 1 1 1 0]

What's the fastest way to find the last 1 in each row? The output should be

ans = [2; 3; 2];

So far I have come up with this:

[~, I] = max(fliplr(A),[],2);
I = size(A,2) + 1  - I;

Answer 1

[KALYAN ACHARJYA]

A=rot90(A,90);
[~,idx]=max(A==1,[],2)

Result:

idx =
     2
     3
     2

Answer 2

[Bruno Luong]

Depending on the density of 1s, but a for-loop (remember that?) might be the fatest

function BenchMax

A=rand(10000)>0.5;

tic
[~, I] = max(fliplr(A),[],2);
I = size(A,2) + 1  - I;
toc % Elapsed time is 0.045622 seconds.

tic
[m,n] = size(A);
I = zeros(m,1);
for r=1:m
    for c=n:-1:1
        if A(r,c)
            I(r) = c;
            break
        end
    end
end
I = n+1-I;
toc % Elapsed time is 0.000437 seconds.
end