problem is that it can not plot x and y,(

조회 수: 3 (최근 30일)
vipul utsav
vipul utsav 2013년 3월 3일
IN GUI,i define handles.matricdata.a=1 in pushbutton1 callback function.
then in pushbutton2 callback function i use
b=handles.matricdata.a;
if(b~=1)
x=[1 2 3 4 5];
y=[5 5 5 5 5]
plot(x,y);
end
then problem is that it can not plot x and y,(if pushbutton1 is not press,then x and y must be plot )

채택된 답변

Azzi Abdelmalek
Azzi Abdelmalek 2013년 3월 3일
You should write in opening function
handles.matricdata.a=0
  댓글 수: 5
Azzi Abdelmalek
Azzi Abdelmalek 2013년 3월 3일
In your yourfilename_OpeningFcn
handles.metricdata.a=0;
guidata(hObject,handles)
vipul utsav
vipul utsav 2013년 3월 3일
thanks

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추가 답변 (1개)

Image Analyst
Image Analyst 2013년 3월 3일
Now why would that not plot when you just set the value to 0 and you're checking if it's not equal to 1. It must go into the if statement. But this is bad code in several ways. What's the point of setting it to 1 in pushbutton1's callback? Why have an "if" in pushbutton2's callback when you directly assign it so you know what the state will be? The if is not necessary in that case. Why do you multiply y by 5? Think about it. If you don't enter the "if" then y will be undefined and it will throw an error. (Though I've already said that you will enter the if because of strange coding.) So in that case, just set y = [25 25 25 25 25] and be done with it.
  댓글 수: 1
vipul utsav
vipul utsav 2013년 3월 3일
i post code just for examples but my main task of pushbuttton1 and pushbutton2 is different. i want that pushbutton2 is display the status of pushbutton1 that whether pushbutton1 is pressed or not? (i.e if pushbutton1 has been pressed and then after i press pushbutton2,it display message 'pb1 is press' using pushbutton2,
and if pushbutton1 has been not pressed and then after i press pushbutton2,it display message 'pb1 is not press' using pushbutton2, in gui)

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