specifying the boundary conditions in pdepe

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Hsn Mtl
Hsn Mtl 2013년 3월 3일
댓글: ahmed 2018년 3월 24일
Hi, I am trying to solve the PDE of a 1D cantilevered beam using pdepe. The main equation is uxxxx=1/u^3. Since it is a fourth order PDE, I have split it into two second order PDEs as: u1xx=u2 u2xx=1/u1^3 Then I defined the relevant C=[0;0],b=[u1x;u2x],s=[-u2;1/u1^3] My problem is in specifying the boundary conditions which are: For the left end: u1(0)=0 , u1x(0)=0 For the right end: u2(1)=0 u2x(1)=0 I can not input this boundary conditions in the standard form to define matrix p and q. Is there any method to solve this problem?

답변 (1개)

Bill Greene
Bill Greene 2013년 3월 3일
Hi,
The equation you show is actually an ordinary differential equation with a single dependent variable u and a single independent variable x rather than a partial differential equation.
The function bvp4c can be used to solve a boundary value problem like the one you show. For bvp4c, your 4th order equation has to be converted to 4 first order equations. This note gives a nice example of how to use bvp4c to solve a linear beam equation:
Extending it to your nonlinear case should be straightforward.
Bill

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