I am not sure what am i doing wrong here.
jday = '190608' % year month day
datetime(jday, 'InputFormat', 'yyMMDD')
this should give me an out put as 8-june-2019
but instead of that it gives me 08-Jan-2019 ! why is this happening ??
i have another question ! i have a time in this format 190608.347009447 - 'yymmdd.ffffffff', 'ffffffff' is the fractional part of the day.
to read this i am using this code !
inputtime = '190608.347009447';
jday = inputtime(1:6);
date(i) = datetime(jday, 'InputFormat', 'yyMMDD') + days(mod(str2double(inputtime), 1))
it gives me an error !!

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Ananthi Jegan
Ananthi Jegan 2020년 11월 19일
편집: Ananthi Jegan 2020년 11월 19일

0 개 추천

For your first question, you have to use the InputFormat as 'yyMMdd' instead of 'yyMMDD'
datetime(jday,'InputFormat','yyMMdd')
Changing the above InputFormat also helps in correcting the second error as well; and to get the datetime including time values as follows
inputtime = '190608.347009447';
jday = inputtime(1:6);
datetime(jday, 'InputFormat', 'yyMMdd') + days(mod(str2double(inputtime), 1))
I hope this helps to correct the errors and to get the results as expected.

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pruth
pruth 2020년 11월 19일
yes sir, it worked perfectly ! thank you !

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질문:

2020년 11월 19일

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2020년 11월 19일

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