How to add strings to an array within a loop

조회 수: 24 (최근 30일)
Sayan Banerjee
Sayan Banerjee 2020년 11월 18일
댓글: Cris LaPierre 2020년 11월 18일
Hello Team, I want to create an array of legend names for a plot. The final array should look like this:
legend_names = ["Case_1", "Case_2", Case_3", ......., "Case_30"]
So, I created a loop to create the variable names,
For ii=1:30
name = sprintf("Case_%d", ii); %%% to create the Case_X names
legend_names = append......?? %%% to create the array as mentioned before
end
Not sure how to construct the array in the loop.
Thanks for your help!

채택된 답변

Cris LaPierre
Cris LaPierre 2020년 11월 18일
If you are using strings, you can create this just using "+".
legend_names = "Case_" + string(1:5)
legend_names = 1×5 string array
"Case_1" "Case_2" "Case_3" "Case_4" "Case_5"
  댓글 수: 2
Sayan Banerjee
Sayan Banerjee 2020년 11월 18일
Thank you so much for the prompt response. Your method is amazing and works fine.
However, in the legend the underscore is interpreted as subscript. How to fix that?
Cris LaPierre
Cris LaPierre 2020년 11월 18일
Set the tex interpreter to none.
legend(legend_names,'Interpreter',"none")

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Ameer Hamza
Ameer Hamza 2020년 11월 18일
편집: Ameer Hamza 2020년 11월 18일
Easier is to use compose()
legend_names = compose('Case_%d', 1:30)
It create a cell array which can be directly use with legend()
legend(legend_names)
You can also directly create a string array
legend_names = compose("Case_%d", 1:30)
  댓글 수: 2
Sayan Banerjee
Sayan Banerjee 2020년 11월 18일
Thank you so much for the prompt response. Your method is compact and works just to create the array.
However, in the legend the underscore is interpreted as subscript. How to fix that?
Ameer Hamza
Ameer Hamza 2020년 11월 18일
Change the line to
legend_names = compose('Case\\_%d', 1:30)

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Legend에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by