for i = 1 :1: N
for j = 1 :1: N
if u(i,j) < 1-a(i,j) && N<1- (u(i,j)/(1-a(i,j)))
z= (1-a(i,j))*N
end
end
end

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Rik
Rik 2020년 11월 17일
This time I edited your question for you. Next time, please use the tools explained on this page to make your question more readable.
What do you mean by 'it doesn't work'?
Also, you don't need loops at all.
z = zeros(size(a));
i = (u < 1-a) && (N < 1 - u./(1-a))
z(i) = (1-a(i)) .* N;
Nirajan Khatri
Nirajan Khatri 2020년 11월 20일
@ Rik thank you, i have u matrix and a matrix so i was trying to use conditional loop, next time i will surely do it
Nirajan Khatri
Nirajan Khatri 2020년 11월 20일
@ Peter Perkins Sir thank you

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도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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2020년 11월 17일

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2020년 11월 20일

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