How to get all the first five columns from a text file?

I am trying to get all the first five columns starting from the third row of this text five.

This is the text file,

http://www.ndbc.noaa.gov/data/realtime2/41053.txt ,

This is the function I created,

 function    Data = SJ 

 fid = fopen( 'SJ.txt' );
        Data = textscan( fid, '%d%d%d%d%d%f%f%f%f%f%s%s%s%f%f%f%f%f%f' ...
                    ,   'Delimiter'             ,   ' '     ...
                    ,   'CollectOutput'         ,   true    ...
                    ,   'HeaderLines'           ,   2       ...
                    ,   'MultipleDelimsAsOne'   ,   true    ...
                    ,   'Whitespace'            ,   ''      ...
                    );
        fclose( fid );
    end

Every time I run it I only get the first five columns of the third row stored on the Data{1,1} cell.

Can you please help?

Answer 1

[per isakson]

Do you really mean "the first five columns"? That's only date and time. However, this format string does that

    '%d%d%d%d%d%*[^\n]'

it says: read the first five columns and skip the rest of the row.

Alternative: Add the line

    ,   'TreatAsEmpty'          ,   'MM'    ...

to textscan. All "MM" in numeric columns will be returned as NaN. Otherwise, reading stops at first "MM" in a numeric column (a column with "%f" in the format).