Exposing graph layout functions

조회 수: 2 (최근 30일)
Marko Budisic
Marko Budisic 2020년 10월 30일
답변: Priysha LNU 2021년 1월 7일
Plotting a graph G involves invoking plot(G), with an option to specify layout, e.g.,
G = graph(...);
plot(G,'Layout','force3');
Is there a way to expose the layout functions that assign coordinates to vertices without going through the machinery of creating a plot itself?
I know I can store the coordinate matrix by calling
Hgraphplot = plot(G, 'Layout','force3');
H.XData, H.YData
but this still generates a figure, axes, and all the associated steps that I'd like to bypass.
So is there a function of the sort
[XData, YData] = layoutcoordinates(G, 'Layout','force3');
whose only job is to generate coordinates?
  댓글 수: 4
Mario Malic
Mario Malic 2020년 10월 30일
Hi,
Is graph the function you might be looking for?
Marko Budisic
Marko Budisic 2020년 10월 30일
Graph creates the object G above, but doesn't assign coordinates to nodes (vertices). I'm interested in the function that assigns coordinates to nodes ("layout" of the graph, to use the same language as MATLAB documentation).

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답변 (1개)

Priysha LNU
Priysha LNU 2021년 1월 7일
Hi,
There is an undocumented way to get the coordinates without actually plotting the graph:
% Construct the graphics chart object without attaching to an axes or figure:
h = matlab.graphics.chart.primitive.GraphPlot('BasicGraph', ...
MLGraph(G), 'Layout', 'force');
% Get its XData and YData properties:
X = h.XData;
Y = h.YData;
The constructor here is an official interface. One can pass in the output of the undocumented method 'MLGraph' to this constructor, which will return an internal representation of the structure of G.
Since this is an internal and undocumented function, it is not officially supported and is subject to change in the future.
If this code were to stop working in the future, one could use "edit graph/plot" and step through the code to find the new internal syntax being used to generate GraphPlot object.
Hope this helps!
Thanks!

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