Error solving three equations in three unknowns
이전 댓글 표시
syms Tan Man Lan eqns vars L av bv cv
Tan =- b - 2 == 0;
Man = c + 1 == 0;
Lan = a + b - 3*c - 1 == 0;
eqns = [Tan Man Lan];
vars = [a b c];
L = solve(eqns,vars,'ReturnConditions',true)
av=L.a
bv=L.b
cv=L.c
Error is Empty sym: 0-by-1
댓글 수: 5
Ameer Hamza
2020년 10월 25일
Which release are you using. I get following result
syms Tan Man Lan eqns vars L av bv cv b c a
Tan =- b - 2 == 0;
Man = c + 1 == 0;
Lan = a + b - 3*c - 1 == 0;
eqns = [Tan Man Lan];
vars = [a b c];
L = solve(eqns,vars,'ReturnConditions',true)
Result
>>
av=L.a
bv=L.b
cv=L.c
av =
0
bv =
-2
cv =
-1
Mohamed Mahmoud
2020년 10월 25일
Ameer Hamza
2020년 10월 25일
Even in MATLAB online, I am getting the correct result. Can you copy and paste the code in my answer and run it?
Mohamed Mahmoud
2020년 10월 25일
John D'Errico
2020년 10월 25일
First, I would point out you seem to think you need to define all of your variables.
syms Tan Man Lan eqns vars L av bv cv
Yet ALL of those variables were defined later.
In fact, the only variables in your code that you never defined as symbolic, were the ones you really need to define! That is, a,b,c all need to be created as symbolic variables, you you never did that.
답변 (1개)
syms a b c
Tan = -b - 2 == 0;
Man = c + 1 == 0;
Lan = a + b - 3*c - 1 == 0;
[av,bv,cv] = solve(Tan,Man,Lan,a,b,c)
This is a linear system, so there is no need even to specify the returnconditions.
As you can see, the only thing I needed to define as symbolic were the variables a,b,c. Everything else is then derived from them.
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