I'm just trying to plot known sphere coordinates:
function sphere(r)
phi = linspace(0,2*pi);
theta = linspace(0,pi);
x = r*cos(phi).*sin(theta);
y = r*sin(phi).*sin(theta);
z = r*cos(theta);
plot3(x,y,z)
end
However this isn't doing the trick. What have I mathematically confounded?

 채택된 답변

J. Alex Lee
J. Alex Lee 2020년 10월 19일

0 개 추천

Your problem is not with conversion or plotting, but defining the coordinates that you want...
[phi,theta] = meshgrid(linspace(0,2*pi),linspace(0,pi));
Also if you didn't know:

댓글 수: 2

Niklas Kurz
Niklas Kurz 2020년 10월 21일
yea, but I wanted to go through the rough way ;)
You could have said additionally that I need to swap plot3(x,y,z) with mesh(x,y,z), but all in all you've been nudging me in the right direction. Thx
sure thing. if you decide you don't want the rough way and you haven't seen it, check
[X,Y,Z] = r*sphere(n)
mesh(X,Y,Z)
% surf(X,Y,Z) % filled in faces
Also check out

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추가 답변 (1개)

Bruno Luong
Bruno Luong 2020년 10월 21일

1 개 추천

function sphere(r)
phi = linspace(0,2*pi);
theta = linspace(0,pi).'; % first change
x = r*cos(phi).*sin(theta);
y = r*sin(phi).*sin(theta);
z = r*cos(theta)+0*phi; % second change, make z same-size 2d array as x and y
plot3(x,y,z);
end

댓글 수: 3

J. Alex Lee
J. Alex Lee 2020년 10월 21일
nice. might be confusing depending on the audience though :)
As a side note, I wish plot also supported "implicit expansion" so you don't have to make the second change. As long as we have committed to the silent syntax, why not go the full nine yards!
What a hoot! Just one thing: what does
.'
stand for?
Bruno Luong
Bruno Luong 2020년 10월 21일
Click on .'

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