I tried to solve problem but I couldn'!

Write a function called between that takes one scalar and two vectors of the same length as input arguments (the function does not have to check the format of the input) and returns one scalar output argument. If it is called like this, n = between(a,u,v), then n is equal to the number of indices ii for which the scalar a is between u(ii) and v(ii) or a is equal to u(ii) or v(ii). Here are some examples for the case in which the length of the vectors is 4:

[zehra ülgen]

>> n = between(4,[5,0 -7 6], [3, 9, 4, 4])

n =

4

>> n = between(5,[5,0 -7 6], [3, 9, 4, 4])

n =

3

>> n = between(6,[5,0 -7 6], [3, 9, 4, 4])

n =

2

>> n = between(9,[5,0 -7 6], [3, 9, 4, 4])

n =

1

>> n = between(10,[5,0 -7 6], [3, 9, 4, 4])

n =

0

Answer 1

[Payam Morsali]

function y=compare(n,A,B)
y=0;
for i=1:length(A)
    if n>=A(i) && n<=B(i)
        y=y+1;
    elseif n>=B(i) && n<=A(i)
        y=y+1;
    end
end
end

[zehra ülgen]

Thank you!

[John D'Errico]

Please don't do assignments for people when they show no effort to do it themselves. This teaches them nothing, except how to get someone else to do their work for them.

[zehra ülgen]

I tried to solve problem.. That's my answer in a different way..

function n = betweenn(a, u, v)

n = sum((u <= a & a <= v) | (v <= a & a <= u));

end