Filling out multiple structures in an if loop

Im trying to set up some data to use in machine learning, but i am having a hard time setting up the data.

Right now im trying to sort my data into different structures according to label.

for k = 1:20
 if  rawData.sub1.run.label{1, 1}.data(k,3) == 0
     classData.sub1.right{k}=rawData.sub1.run.epochs.run1.movement{k}
    elseif rawData.sub1.run.label{1, 1}.data(k,3) == 1
     classData.sub1.up{k}=rawData.sub1.run.epochs.run1.movement{k}
    elseif rawData.sub1.run.label{1, 1}.data(k,3) == 2
     classData.sub1.left{k}=rawData.sub1.run.epochs.run1.movement{k}
    elseif rawData.sub1.run.label{1, 1}.data(k,3) == 3
     classData.sub1.down{k}=rawData.sub1.run.epochs.run1.movement{k} 
 end
end

My problem is the "right{k}" ... down{k} structures.

if i dont input a k, the loop will simply replace the data that is already placed in the structure with the new data that belongs in the scructure.

However if i give the input k, multiple cells inside the structure is left as null, making it hard to call for the data again.

I've been reading up on structures but cant seem to find a simple solution.

i was thinking if it was possible to have a integer that only changed value every forth loop?

Any ideas are appreciated

Answer 1

[Ameer Hamza]

If you want an integer which only increment every fourth iteration then you can use ceil() or floor() functions. For example

for k = 1:20
    disp(ceil(k/4))
end

Result

>> for k = 1:20
    disp(ceil(k/4))
end
     1
     1
     1
     1
     2
     2
     2
     2
     3
     3
     3
     3
     4
     4
     4
     4
     5
     5
     5
     5

[Tim Johansson]

Thank you very much!

[Ameer Hamza]

I am glad to be of help!!!