splitting up numbers in a cell of a double

Hi,

I have a 22x1 double array with numbers such as 0100001 0100100 in each cell. How would i split this up into a 154x1 (22*7) vector with

0

1

0

0

0

0

1

0

1

0

0

1

0

0

etc

Answer 1

[Star Strider]

See if the num2cell function will do what you want.

EDIT — (13 Oct 2020 at 12:53)

(Question was essentially completely changed.)

To clarify, it is not a double array, because the leading zeros would not be present. Most likely is’s a cell array:

v = {'0100001' '0100100'};

and it’s relatively straightforward (although not at all obvious) to get the result you want:

Out = reshape([v{:}]-'0', [],1)

producing:

Out =
     0
     1
     0
     0
     0
     0
     1
     0
     1
     0
     0
     1
     0
     0

.

[Abbey Stock]

i have tried that and it dosent work :(

[Star Strider]

The num2cell approach would not work with your edited Question.

Please see if my edited Answer does what you want. I was writing it while you were posting your Comment.

[Abbey Stock]

hi,

The way with {;} produced an error but when using reshape([x]-'0', 1,[]); it reads down the rows instead of across the columns, so i end up with 0 0 1 1 etc instead of 01.. 01..

[Star Strider]

Brace indexing would not work for a double array, only a cell array.

Something is not correct, since a double would not have leading zeros.

It would help to see the actual original data, most likely as a .mat file.

(13:12 UCT) With respect to your edited Comment, I am now thoroughly lost. I have no idea what your data actually are, much less how to deal with what appears to be a moving target.

Answer 2

[madhan ravi]

Wanted = vertcat(cell_array{:})
%or
Wanted = cat(1, cell_array{:})

[Abbey Stock]

hi, i just get 'Brace indexing is not supported for variables of this type'

[madhan ravi]

cell_array = {[0,1,0,0,0,0,1].', [0,1,0,0,1,0,0].'};
Wanted = vertcat(cell_array{:})
%or
Wanted = cat(1, cell_array{:})