for loop taking too long to operate

조회 수: 12 (최근 30일)
SChow
SChow 2020년 10월 6일
댓글: SChow 2020년 10월 6일
I have a matrices (b1 and popx) with size 25000x50000, code is a vector which contains unique values in b1 (of length 300). For elements in popx which correspond to each unique value of b1, I need the sum of popx,
The below code takes very long (>2 hours) to operate, Any help to lower computation time is much appreciated
for i=1:300
popx1=popx;
popx1(b1~=code(i))=NaN;
popn=nansum(nansum(popx1));
popn1(i)=popn;
end;

채택된 답변

Jos (10584)
Jos (10584) 2020년 10월 6일
Pre-allocation, and recoding using logical indexing and sum should speed things up
popn1 = nan(300,1) ; % pre-allocation
for i=1:300
tf = b1 == code(i) ;
popn1(i) = sum(popx(tf), 'all') ;
end;

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by