Efficient way/best practice to slice array under a logical condition as well as other conditions
    조회 수: 9 (최근 30일)
  
       이전 댓글 표시
    
I did not know how to properly title this question, so please bear with me.
Simply put, with the following two arrays:
A = [0 1 0 1 0 0 0 1]'
B = [800    1	1	60;
    900	    3	0	30;
    900	    4	0	30;
    900	    6	0	30;
    900	    7	0	30;
    900	    11	0	30;
    900	    1	2	60;
    1000    1	2	60;
]
Note that A and B have the same number of columns.
I would like, for example, to slice B under the following constraints:
- A == 1
- B(:,3) ~= 0
- Keep only columns [2 3 4] of B
This is the way I am doing it at the moment:
B_sliced = B(A==1 & B(:,3)~=0,[2 3 4]);
Alternatively, one could do:
B_sliced = B(logical(A) & B(:,3)~=0,[2 3 4]);
With tic toc and large matrices, I am not noticing much of a difference in performance.
Is there a best practice regarding combining logical with non-logical conditions? Should I keep something in mind, or it doesn't really matter which way I go? Is there a way to make any of these more efficient by using "find"?
I hope you can enlighten me a bit! Thanks.
댓글 수: 1
  Bruno Luong
      
      
 2020년 10월 4일
				
      편집: Bruno Luong
      
      
 2020년 10월 4일
  
			Don't split the hair, it doesn't really matter.
Just do the way te code looks most readable to you.
답변 (1개)
참고 항목
카테고리
				Help Center 및 File Exchange에서 Logical에 대해 자세히 알아보기
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!


