How to suppress this error?

조회 수: 31 (최근 30일)
Jakob Sievers
Jakob Sievers 2020년 9월 25일
답변: Real User 2024년 3월 21일
Hi there
I am receiving the following error message:
Warning: Matrix is singular, close to singular or badly scaled. Results may be inaccurate. RCOND = NaN.
> In mpower>integerMpower (line 80)
In ^ (line 49)
In gaussfit (line 111)
The line in question is:
a = (F2)^(-1)*F'*(y-f0) + a0;
I wish to suppress, not solve, this problem and so I added the following to the beginning of my script, and yet still receive the error message. What am I doing wrong?
warning('off','MATLAB:singularMatrix')
  댓글 수: 4
Jakob Sievers
Jakob Sievers 2020년 9월 25일
This is not a script I originally wrote so I couldn't say. It just worked for my purpose. Though if you have a better way, not to mention a faster way, of doing it I am all ears. My process involves using this equation quite often and would love to shave some time off of it if possible.
Jakob Sievers
Jakob Sievers 2020년 9월 25일
I just had a look and the file (which fits a gaussian curve) is from 2012, so it might indeed be overdue for an update:
function [sigma, mu,error] = gaussfit( x, y, sigma0, mu0,runmode,idix)
% [sigma, mu] = gaussfit( x, y, sigma0, mu0 )
% Fits a guassian probability density function into (x,y) points using iterative
% LMS method. Gaussian p.d.f is given by:
% y = 1/(sqrt(2*pi)*sigma)*exp( -(x - mu)^2 / (2*sigma^2))
% The results are much better than minimazing logarithmic residuals
%
% INPUT:
% sigma0 - initial value of sigma (optional)
% mu0 - initial value of mean (optional)
%
% OUTPUT:
% sigma - optimal value of standard deviation
% mu - optimal value of mean
%
% REMARKS:
% The function does not always converge in which case try to use initial
% values sigma0, mu0. Check also if the data is properly scaled, i.e. p.d.f
% should approx. sum up to 1
%
% VERSION: 23.02.2012
%
% EXAMPLE USAGE:
% x = -10:1:10;
% s = 2;
% m = 3;
% y = 1/(sqrt(2*pi)* s ) * exp( - (x-m).^2 / (2*s^2)) + 0.02*randn( 1, 21 );
% [sigma,mu] = gaussfit( x, y )
% xp = -10:0.1:10;
% yp = 1/(sqrt(2*pi)* sigma ) * exp( - (xp-mu).^2 / (2*sigma^2));
% plot( x, y, 'o', xp, yp, '-' );
warning off;
warning('off','MATLAB:singularMatrix')
error=0; %no error
% Maximum number of iterations
Nmax = 50;
if nargin==4
runmode=1; %output warnings!
end
if( length( x ) ~= length( y ))
fprintf( 'x and y should be of equal length\n\r' );
exit;
end
n = length( x );
x = reshape( x, n, 1 );
y = reshape( y, n, 1 );
%sort according to x
X = [x,y];
X = sortrows( X );
x = X(:,1);
y = X(:,2);
%Checking if the data is normalized
dx = diff( x );
dy = 0.5*(y(1:length(y)-1) + y(2:length(y)));
s = sum( dx .* dy );
if( s > 1.5 | s < 0.5 )
fprintf( 'Data is not normalized! The pdf sums to: %f. Normalizing...\n\r', s );
error=1;
y = y ./ s;
end
X = zeros( n, 3 );
X(:,1) = 1;
X(:,2) = x;
X(:,3) = (x.*x);
% try to estimate mean mu from the location of the maximum
[ymax,index]=max(y);
mu = x(index);
% estimate sigma
sigma = 1/(sqrt(2*pi)*ymax);
if( nargin == 3 )
sigma = sigma0;
end
if( nargin == 4 )
mu = mu0;
end
%xp = linspace( min(x), max(x) );
% iterations
ii=0;
while ii<Nmax
ii=ii+1;
% yp = 1/(sqrt(2*pi)*sigma) * exp( -(xp - mu).^2 / (2*sigma^2));
% plot( x, y, 'o', xp, yp, '-' );
dfdsigma = -1/(sqrt(2*pi)*sigma^2)*exp(-((x-mu).^2) / (2*sigma^2));
dfdsigma = dfdsigma + 1/(sqrt(2*pi)*sigma).*exp(-((x-mu).^2) / (2*sigma^2)).*((x-mu).^2/sigma^3);
dfdmu = 1/(sqrt(2*pi)*sigma)*exp(-((x-mu).^2)/(2*sigma^2)).*(x-mu)/(sigma^2);
F = [ dfdsigma dfdmu ];
a0 = [sigma;mu];
f0 = 1/(sqrt(2*pi)*sigma).*exp( -(x-mu).^2 /(2*sigma^2));
if any(isnan(F(:)))
error=1;
ii=Nmax;
else
F2=F'*F;
if rank(F2)<min(size(F))
error=1;
ii=Nmax;
else
a = (F2)^(-1)*F'*(y-f0) + a0;
sigma = a(1);
mu = a(2);
if( sigma < 0 )
sigma = abs( sigma );
if runmode==1
fprintf( 'Instability detected! Rerun with initial values sigma0 and mu0! \r' );
fprintf( 'Check if your data is properly scaled! p.d.f should approx. sum up to 1 \r' );
end
error=1;
ii=Nmax;
end
end
end
end

댓글을 달려면 로그인하십시오.

답변 (2개)

the cyclist
the cyclist 2020년 9월 25일
Two thoughts:
First: Are you certain you have the correct warning? After you run your code that gives the warning, what is the output of
w = warning('query','last')
(Your warning does look like it matches the one you are turning off, so I'm guessing that's not the issue.)
Second: I believe that turning off warnings only persists for the session. Does this warning happen during the same session in which you turned it off?
  댓글 수: 1
Jakob Sievers
Jakob Sievers 2020년 9월 25일
The above solution worked for my needs. Thanks for your attention though :)

댓글을 달려면 로그인하십시오.


Real User
Real User 2024년 3월 21일
warning('off','MATLAB:nearlySingularMatrix')
But the cyclist's answer works for any error (that's how I found this).

카테고리

Help CenterFile Exchange에서 Mathematics and Optimization에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by