vectorizing or speeding looped code

조회 수: 7 (최근 30일)
Paul Schenk
Paul Schenk 2020년 9월 22일
댓글: Paul Schenk 2020년 9월 23일
i am trying to speed up some code with multiple functions and have found the one that takes the most time (it is all a converted fortran code). it runs a nested for loop 4 times (each with modified input). i've had some success elsewhere in the code eliminating slow points but this one just cant get right. any ideas? (in 2016b for compatability reasons)
for II= 1:N
XP(1)= 1.0D0;
for JJ=2:IORD1
XP(JJ)=XP(JJ-1)*double(A1(II));
end
for JJ= 1:IORD1
for KK= 1:IORD1
B(JJ,KK)=B(JJ,KK)+XP(JJ)*XP(KK);
end
C(JJ)=C(JJ)+XP(JJ)*A2(II);
end
end

답변 (3개)

Turlough Hughes
Turlough Hughes 2020년 9월 22일
This should help, though I've already made assumptions about the sizes of arrays. How many rows/columns are in each variable?
XP(1) = 1;
for II= 1:N
XP(2:end) = XP(1:end-1)*double(A1(II));
B = B + XP(:).*XP(:).';
C = C + XP*A2(II);
end
  댓글 수: 2
Paul Schenk
Paul Schenk 2020년 9월 22일
the dimensions change (get smaller) in each of the 4 runs. they will have to be declared each time.
Turlough Hughes
Turlough Hughes 2020년 9월 22일
Did the code work?
Some questions: is XP a column vector/row vector? Does A2 have as many elements as XP? Also, does B contain IORD1 rows and columns? Similarly does C have IORD1 elements?

댓글을 달려면 로그인하십시오.


Paul Schenk
Paul Schenk 2020년 9월 22일
not as entered. tripled cpu time.
here are preallo's to variables:
ORDER_MAX = 20;
C = zeros(ORDER_MAX+1,1);
IORD=MAXOR;
IORD1=IORD+1;
B = single(zeros(ORDER_MAX+1,ORDER_MAX+1)); % Solution matrix
XP = double(zeros(ORDER_MAX+1,1)); % Array of solutions
  댓글 수: 2
Paul Schenk
Paul Schenk 2020년 9월 22일
a1 and a2 are linear (1,2000) arrays that are usually only 10% filled in.
Turlough Hughes
Turlough Hughes 2020년 9월 23일
Vectorisation is usually faster but not always. Probably best to just provide a minimum working example (google it) of code that I (or others) can test and profile. Otherwise it really is just guess work.

댓글을 달려면 로그인하십시오.


Paul Schenk
Paul Schenk 2020년 9월 23일
hope this works for you. it is essentially a customized LS fit solution.
  댓글 수: 4
Turlough Hughes
Turlough Hughes 2020년 9월 23일
eqor=1 ? I assume that's MAXOR?
Paul Schenk
Paul Schenk 2020년 9월 23일
yes, my mistake!

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by