Passing Function results to another function
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I recently ran into some behavior I though was unintuitive - given the code below, nargin prints out 1. Why isn't the second argument being passed to test2? Is there a standard way to get around this issue?
test2(test())
1
function [a,b] = test( )
a=5;
b=6;
end
function test2( a,b)
nargin
end
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도움말 센터 및 File Exchange에서 Creating, Deleting, and Querying Graphics Objects에 대해 자세히 알아보기
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