How can we define a function with variables which are in the for loop and function is also under for loop?

I want to define the function as

For i=1:100

fi(x0,x1, x2, ....xi)=x0^2+x1^2+.....xi^2

end

where for loop is on the functions(fi) as well as on the variables.

[KSSV]

Question is not clear.

[Surath Ghosh]

Please check the question now.

[Stephen23]

"but I have to write 1000 functions of 1000 variables. what should I do now??"

Use arrays and indexing, then you can solve your task efficiently using MATLAB.

Using 1000 different variables would not be a good use of MATLAB.

[Surath Ghosh]

Please see the pdf

Answer 1

[KSSV]

Read about anonymous function.

EXample:

f = @(x1,x2,x3) 2*x1.^3+3*x2.^2+x3 ;
x1 = rand(10,1) ; x2 = rand(10,1) ; x3 = rand(10,1) ;
val = f(x1,x2,x3) 

[Surath Ghosh]

Okay. Thanks a lot.

In this case you have taken one function of three variables but I have to write 1000 functions of 1000 variables. what should I do now??

[KSSV]

You are not supposed to have like that...that case, you need to collect them into a matrix and do the below:

f = @(x1,x2,x3) x1.^2+x2.^2+x3.^2 ;
x1 = rand(10,1) ; x2 = rand(10,1) ; x3 = rand(10,1) ;
val = f(x1,x2,x3) 

p = sum([x1 x2 x3].^2,2) ;   % you need to do this 

[Steven Lord]

I recommend not having your function accept 1000 separate input arguments. Write one general function.

f = @(x) sum(x.^2);

Now you can call it with however long a vector you want.

f(1:5)
f(1:10)
f(2:2:8)

If you're using a sufficiently recent release, you could even have f accept arrays.

g = @(x) sum(x.^2, 'all');
g(magic(3))

Answer 2

[Ameer Hamza]

If you want to have a variable number of inputs, you can use varargin

f = @(varargin) sum([varargin{:}].^2);

Result

>> f(1,1,5)
ans =
    27
>> f(1,1,5,22,32,34,1,2,3,4,5,1,2,3,45,32,23,10)
ans =
        6438

[Surath Ghosh]

Please check pdf