quad2d: Reached the maximum number of function evaluations

조회 수: 1 (최근 30일)
Jinsoo
Jinsoo 2013년 1월 16일
댓글: Walter Roberson 2017년 7월 31일
I'm trying to find the error in the following code. I want to iterate:
for iter = 1:10
% uallA = Int_GLA.*(-Int_GC - Int_GB) + Int_GA;
uallA = Int_GLA.*(-uallC - uallB) + Int_GA;
uallB = Int_GLB.*(-uallC - uallB) + Int_GB;
uallC = Int_GLC.*(-uallC - uallB) + Int_GC;
end
However, I receive the following error:
Warning: Reached the maximum number of function evaluations (2000). The result fails the global error test.
This is my code:
clc; clear all; close all;
x = linspace(-10, 10, 51);
t = linspace(0.1, 5, 51);
nx = length(x);
nt = length(t);
Wx = x(2) - x(1);
Wt = t(2) - t(1);
f = @(x) exp(-x.^2);
%%A right
for mx = 1:nx
for mt = 1:nt
GA = @(xi) 1./sqrt(4*pi*(t(mt))).*exp(-(x(mx) - xi).^2./(4*(t(mt)))).*exp(-xi.^2);
funGA = quad(GA, x(1), x(end));
Int_GA(mx, mt) = funGA;
end
end
figure(1)
surf(t,x, Int_GA)
xlabel('t')
ylabel('x')
zlabel('u')
%%B right
for mx = 1:nx
for mt = 1:nt
GB = @(xi) 1./sqrt(4*pi*(t(mt))).*exp(-(x(mx) - xi).^2./(4*(t(mt))))...
.*(-(x(mx) - xi)/(2*t(mt))).*exp(-xi.^2);
funGB = quad(GB, x(1), x(end));
Int_GB(mx, mt) = funGB;
end
end
figure(2)
surf(t,x, Int_GB)
xlabel('t')
ylabel('x')
zlabel('u')
%%C right
for mx = 1:nx
for mt = 1:nt
GC = @(xi) 1./sqrt(4*pi*(t(mt))).*exp(-(x(mx) - xi).^2./(4*(t(mt))))...
.*((x(mx)-xi).^2/(4*t(mt).^2) - 1./(2*t(mt))).*exp(-xi.^2);
funGC = quad(GC, x(1), x(end));
Int_GC(mx, mt) = funGC;
end
end
figure(3)
surf(t,x, Int_GC)
xlabel('t')
ylabel('x')
zlabel('u')
%%A left
for mt1 = 1:nt
for mx1 = 1:nx
GLA = @(xi, ta) 1./sqrt(4*pi*(t(mt1)-ta)).*exp(-(x(mx1) - xi).^2 ...
./(4*(t(mt1)-ta)));
funGLA = quad2d(GLA, x(1), x(end), t(1), t(mt1), 'AbsTol',1e-4, 'FailurePlot',true);
Int_GLA(mx1, mt1) = funGLA;
end
end
figure(4)
surf(t,x, Int_GLA)
xlabel('t')
ylabel('x')
zlabel('u')
%%B left
for mt2 = 1:nt
for mx2 = 1:nx
GLB = @(xi, ta) -(x(mx2) - xi)./(2*(t(mt2) - ta))./sqrt(4*pi*(t(mt2)-ta))...
.*exp(-(x(mx2) - xi).^2 ./(4*(t(mt2)-ta)));
funGLB = quad2d(GLB, x(1), x(end), t(1), t(mt2), 'AbsTol',1e-4, 'FailurePlot',true);
Int_GLB(mx2, mt2) = funGLB;
end
end
%%C left
for mt3 = 1:nt
for mx3 = 1:nx
GLC = @(xi, ta) 1./(4*(t(mt3)-ta).^2).*((x(mx3) - xi).^2 - ...
2*(t(mt3)-ta))./sqrt(4*pi*(t(mt3)-ta)).*exp(-(x(mx3) - xi).^2 ...
./(4*(t(mt3)-ta)));
funGLC = quad2d(GLC, x(1), x(end), t(1), t(mt3), 'AbsTol',1e-4, 'FailurePlot',true);
Int_GLC(mx3, mt3) = funGLC;
end
end
uallB = zeros(nx, nt);
uallC = zeros(nx, nt);
for iter = 1:10
% uallA = Int_GLA.*(-Int_GC - Int_GB) + Int_GA;
uallA = Int_GLA.*(-uallC - uallB) + Int_GA;
uallB = Int_GLB.*(-uallC - uallB) + Int_GB;
uallC = Int_GLC.*(-uallC - uallB) + Int_GC;
end
% uallA1 = Int_GA;
% uallB1 = Int_GB;
% uallC1 = Int_GC;
% uallA = Int_GLA.*(-uallC1 - uallB1) + Int_GA;
figure(5)
surf(t,x, uallA)
xlabel('t')
ylabel('x')
zlabel('u')

채택된 답변

Walter Roberson
Walter Roberson 2013년 1월 16일
The problem is not occurring in the "for iter" loop that you point out: it is occurring in the quad2d() call.
You should add a MaxFunEvals parameter to your quad2d() call.
Also you should be examining your failure plot.
  댓글 수: 4
Torsten
Torsten 2017년 7월 31일
Please show your code.
Best wishes
Torsten.
Walter Roberson
Walter Roberson 2017년 7월 31일
I think you missed the ' marks around MaxFunEvals

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Surface and Mesh Plots에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by